Question

Molly can prepare a report in 6 hours. Jere can prepare a report in only 4 hours.

Answer 1

Answer with explanation:

Time taken by Molly to prepare the Report = 6 hours

Work done in 1 hour $=\frac{1}{6}$

Time taken by Jere to prepare the Report = 4 hours

Work done in 1 hour $=\frac{1}{4}$

Their Combined Work , is given by the equation

          $=\frac{1}{6}+\frac{1}{4}\\\\=\frac{6+4}{6\times 4}\\\\=\frac{10}{24}$

Time it would take for Molly and Jere to prepare a report together is equal to

       $=\frac{24}{10}\\\\=2.4$

= 2.4 hours

             

Answer 2

Answer:

Total time taken by Molly and Jere to prepare a report together = 2.4 hours  

Step-by-step explanation:

Time taken by Molly to prepare a report = 6 hours

$\text{So, one hour work of Molly = }\frac{1}{6}\text{ hours}$

Time taken by Jere to prepare a report = 4 hours

$\text{So, one hour work of Jere = }\frac{1}{4}\text{ hours}$

Now, we need to calculate the total time taken by Molly and Jere to prepare a report together.

$\text{Time taken by Molly and Jere to prepare a report together = }\frac{1}{6}+\frac{1}{4}\\\\\implies \frac{6+4}{24}\\\\\implies \frac{10}{24}\\\\\implies \text {Total time taken by Molly and Jere to prepare a report together = }\frac{24}{10} =2.4\text{ hours}$

Hence, Total time taken by Molly and Jere to prepare a report together = 2.4 hours