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stepladder [879]
3 years ago
5

What is the value of x when the Richter scale rating is 4.4? Round your answer to the nearest hundredth. Pls help

Mathematics
1 answer:
Lemur [1.5K]3 years ago
5 0

Hello,

We have to use this relation : \text{rating}=\log(\text{ratio})

He we have :

\log_{10}(x)=4.4\\\\\text{then }x=10^{\log_{10}(x)}\\\\\rightarrow x=10^{4.4}\\\\\rightarrow x=25\ 118.864\\\rightarrow x=25\ 118.86


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A teacher used the change of base formula to determine whether the equation below is correct.
Mademuasel [1]

Answer:

The equation is correct

Step-by-step explanation:

The equation, written as:

[log_2 (10)][log_4 (8)][log_10 (4)] = 3

Consider the change of base formula:

log_a (x) = [log_10 (x)]/ [log_10 (a)]

Applying the change of base formula to change the expressions in base 2 and base 4 to base 10.

(1)

log_2 (10) = [log_10 (10)]/[log_10 (2)]

= 1/[log_10 (2)]

(Because log_10 (10) = 1)

(2)

log_4 (8)  = [log_10 (8)]/[log_10 (4)]

Now putting the values of these new logs in base 10 into the left-hand side of original equation to verify if we have 3, we have:

[log_10 (2)][log_8 (4)][log_10 (4)]

= [1/ log_10 (2)][log_10 (8) / log_10 (4)][log_10 (4)]

= [1/log_10 (2)] [log_10 (8)]

= [log_10 (8)]/[log_10 (2)]

= [log_10 (2³)]/[log_10 (2)]

Since log_b (a^x) = xlog_b (a)

= 3[log_10 (2)]/[log_10 (2)]

= 3 as required

Therefore, the left hand side of the equation is equal to the right hand side of the equation.

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nalin [4]

Answer:

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Step-by-step explanation:

(n+4)/10 = (n-8)/2

We can solve using cross products

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