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chubhunter [2.5K]
3 years ago
12

\begin{aligned} &A = 7x^2-3x+10 \\\\ &B = -4x^2+6x-4 \end{aligned} ​ A=7x 2 −3x+10 B=−4x 2 +6x−4 ​ A-B=A−B=A, minus, B,

equals Your answer should be a polynomial in standard form.
Mathematics
1 answer:
fgiga [73]3 years ago
4 0

Answer:

<h2>A-B = 11x²-9x+14</h2>

Step-by-step explanation:

Given the polynomial functions A = 7x^2-3x+10 and B = -4x^2+6x-4, we are to find the value of A - B.

A-B =  7x²-3x+10 - ( -4x²+6x-4)

open the parenthesis

A-B = 7x²-3x+10 + 4x²-6x+4

collect the like terms

A-B  = 7x² + 4x²-3x-6x+10+4

A-B = 11x²-9x+14

<em>Hence the difference between both quadratic equation in standard form is 11x²-9x+14</em>

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Answer:

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Step-by-step explanation:

Radio talk show host asked listeners to respond therefore the population is all listeners of the radio talk show.

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Step-by-step explanation:

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A. Find PR in the diagram <br> b. Find the perimeter of quadrilateral PQRS
Elan Coil [88]

Answer:

Step-by-step explanation:

The quadrilateral has 4 sides and only two of them are equal.

A) to find PR, we will consider the triangle, PRQ.

Using cosine rule

a^2 = b^2 + c^2 - 2abcos A

We are looking for PR

PR^2 = 8^2 + 7^2 - 2 ×8 × 7Cos70

PR^2 = 64 + 49 - 112 × 0.3420

PR^2 = 113 - 38.304 = 74.696

PR = √74.696 = 8.64

B) to find the perimeter of PQRS, we will consider the triangle, RSP. It is an isosceles triangle. Therefore, two sides and two base angles are equal. To determine the length of SP,

We will use the sine rule because only one side,PR is known

For sine rule,

a/sinA = b/sinB

SP/ sin 35 = 8.64/sin110

Cross multiplying

SPsin110 = 8.64sin35

SP = 8.64sin35/sin110

SP = (8.64 × 0.5736)/0.9397

SP = 5.27

SR = SP = 5.27

The perimeter of the quadrilateral PQRS is the sum of the sides. The perimeter = 8 + 7 + 5.27 + 5.27 = 25.54 cm

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2 years ago
True or False? A triangle can have side lengths of 3, 3 , and 6
asambeis [7]

Answer:

No

Step-by-step explanation:

We can check with the Pythagorean Theorem.

a^2 + b^2 = c^2

  a and b are always the smaller sides, the legs

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3^2 + 3^2 >  6^2

9 + 9 > 36

18 < 36

18 is not greater than 36, therefore this triangle can not have the side lengths 3, 3, and 6.

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2 years ago
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