How many prime numbers between 8 and 60 leave a remainder of 2 when divided by 6?

1 answer:

3 0

Hey there!! :D

Prime Number: Is a natural number greater than 1 that cannot be formed by multiplying two smaller natural numbers.

If you list out all of the prime numbers between 8 and 60 and divide each one by 6, you will notice that the remainder ends with either 1or 5 and not 2.

So your answer would be A) 0

Hope this helps!!

Have A Fantastic Weekend!!

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The length of side AI is?

marissa [1.9K]

Answer:

AI=3.25 IH= 4.2

Step-by-step explanation

The distance between C and D is 1.3 inches, the distance between E and F is 0.75 inches and the distance between G and H is 1.2 inches. This is true because the model says so. If you look closely together, this is equal to the distance between AI which is the length of AI. The answer would be 1.2+1.3+0.75=3.25. To find the length of side IH you do the same strategy, the distance between sides D and E is 4.8 inches, at the bottom is 9 inches of distance between side I and side F. 9-4.8 inches is equal to 4.2 inches. Therefore, the length of side AI is 3.25 inches and the length of side IH is 4.2 inches. If I am wrong please tell me for feedback, I also hoped that this has helped you in your learning :)

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2 years ago

Read 2 more answers

Suppose there is a pile of quarters dimes and pennies with a total value of $1.07 how much of each coin can be present without b

Korolek [52]

Hello,

Very nice as problem.

2 solutions:
1 quater,8 dimes, 2 pennies
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since
107=( 0, 0, 107) but : 100= 0*25+ 0*10+ 100
107=( 0, 1, 97) but : 100= 0*25+ 1*10+ 90
107=( 0, 2, 87) but : 100= 0*25+ 2*10+ 80
107=( 0, 3, 77) but : 100= 0*25+ 3*10+ 70
107=( 0, 4, 67) but : 100= 0*25+ 4*10+ 60
107=( 0, 5, 57) but : 100= 0*25+ 5*10+ 50
107=( 0, 6, 47) but : 100= 0*25+ 6*10+ 40
107=( 0, 7, 37) but : 100= 0*25+ 7*10+ 30
107=( 0, 8, 27) but : 100= 0*25+ 8*10+ 20
107=( 0, 9, 17) but : 100= 0*25+ 9*10+ 10
107=( 0, 10, 7) but : 100= 0*25+ 10*10+ 0
107=( 1, 0, 82) but : 100= 1*25+ 0*10+ 75
107=( 1, 1, 72) but : 100= 1*25+ 1*10+ 65
107=( 1, 2, 62) but : 100= 1*25+ 2*10+ 55
107=( 1, 3, 52) but : 100= 1*25+ 3*10+ 45
107=( 1, 4, 42) but : 100= 1*25+ 4*10+ 35
107=( 1, 5, 32) but : 100= 1*25+ 5*10+ 25
107=( 1, 6, 22) but : 100= 1*25+ 6*10+ 15
107=( 1, 7, 12) but : 100= 1*25+ 7*10+ 5
107=( 1, 8, 2) is good
107=( 2, 0, 57) but : 100= 2*25+ 0*10+ 50
107=( 2, 1, 47) but : 100= 2*25+ 1*10+ 40
107=( 2, 2, 37) but : 100= 2*25+ 2*10+ 30
107=( 2, 3, 27) but : 100= 2*25+ 3*10+ 20
107=( 2, 4, 17) but : 100= 2*25+ 4*10+ 10
107=( 2, 5, 7) but : 100= 2*25+ 5*10+ 0
107=( 3, 0, 32) but : 100= 3*25+ 0*10+ 25
107=( 3, 1, 22) but : 100= 3*25+ 1*10+ 15
107=( 3, 2, 12) but : 100= 3*25+ 2*10+ 5
107=( 3, 3, 2) is good
107=( 4, 0, 7) but : 100= 4*25+ 0*10+ 0

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3 years ago

Since people are sad they missed my 50 points, here is 100 points for the first 2 to answer. First one gets branliest aswell.

svetoff [14.1K]

Ummm is there something I Guccie

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2 years ago

Order from least to greatest

Orlov [11]

Answer:
In order from least to greatest: 0.25, 3 ⅜, 3 ⅖;

Or, write as: 0.25 < 3 ⅜ < 3 ⅖ .
___________________________________
Explanation:

0.25 = ¼ l (less than "1"); the lowest of the three given values.

The remaining two values have the same whole number of 3, and a fraction:
3 ⅖ ; and 3 ⅜.

The least common multiples among the denominators of the fraction values is 40. ⅖ = ?/40 ; 5*? =40? 5* 8 = 40, so 2*8 = 16;
Thus, ⅖ = 16/40, and 3 ⅖ = 3 16/40. 3/8 = ?/40? 8*5 =40; so 3*5 = 15 ; thus ⅜ = 15/40; and
and 3 ⅜ = 3 15/40.
3 15/40 is less than than 3 16/40;
as such; 3 ⅜ is less than 3 ⅖.

So, in order from least to greatest: 0.25, 3 ⅜, 3 ⅖;
Or, write as: 0.25 < 3 ⅜ < 3 ⅖ .

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3 years ago

−125%+20/28= help plzz

wlad13 [49]

-125%+20/28
-125/100+20/28
ANSWER: -15/28

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3 years ago