Answer:
See answers below
Step-by-step explanation:
T59 = a+58d = -61
T4 = a+3d = 64.
Subtract
58d-3d = -61-64
-55d = -125
d =125/55
d = 25/11
Get a;
From 2
a+3d = 64
a+3(25/11) = 64
a = 64-75/11
a = 704-75/11
a = 629/11
T23 = a+22d
T23 = 629/11+22(25/11)
T23 = 1179/11
Given that the sides of the acute triangle are as follows:
21 cm
x cm
2x cm
Stated that 21 cm is one of the shorter sides of the triangle2x is greater than x, so it follows that 2x MUST be the longest side
For acute triangles, the longest side must be less than the sum of the 2 shorter sides
Therefore, 2x < x + 21cm
2x – x < 21cm
x < 21cm
If x < 21cm, then 2x < 42cm
Therefore, the longest possible length for the longest side is 42cm
Answer:
x = 113
Step-by-step explanation:
Vertical angles are congruent. To the left of 113 would be 67 but x is not.
Since the triangles are similar, then 32 = x+7 those two angles are too
solve for "x"
now using proportions
solve for JK
solve for KG
the scale factor of the perimeter of both triangles is just the same as the ratio of the sides, or
The shortest distance between 2 concentric circles is the difference of their radii. Thus the answer is 8-2=6
