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MakcuM [25]
4 years ago
15

Indicate the method you would use to prove the two 's . If no method applies, enter "none".HL

Mathematics
2 answers:
artcher [175]4 years ago
5 0

Answer : HA

Indicate the method you would use to prove the two 's

HL  -> It represents Hypotenuse Leg. In the figure , the hypotenuse are same but not the length.

LA  --> It represents Leg Angle . In the figure ,  the corresponding legs and angle are not same.

LL  --> It represents Leg Leg . In the figure ,  the corresponding legs  are not same.

HA--> It represents Hypotenuse Angle . In the figure ,   In the figure , the corresponding hypotenuse and angles  are same.


quester [9]4 years ago
5 0
THE ANSWER THAT YOUR LOOKING FOR IS  D

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Which shows how to find the value of this expression when x=-2 and y=5? <br> (3x^3y^-2)2
Gnoma [55]

Put x = -2 and y = 5 to the expression.

(3x^3y^{-2})^2

\left[3\cdot(-2)^3(5)^{-2}\right]^2=\left[3(-8)\cdot\dfrac{1}{5^2}\right]^2=\left(-24\cdot\dfrac{1}{25}\right)^2=\left(-\dfrac{24}{25}\right)^2\\\\=\dfrac{24^2}{25^2}=\dfrac{576}{625}

explanation

(-2)^3=(-2)(-2)(-2)=-8\\\\a^{-n}=\dfrac{1}{a^n}\to5^{-2}=\dfrac{1}{5^2}=\dfrac{1}{(5)(5)}=\dfrac{1}{25}\\\\a^2\geq0\ \text{for any real number}\to\left(-\dfrac{24}{25}\right)^2=\left(\dfrac{24}{25}\right)^2\\\\\left(\dfrac{a}{b}\right)^2=\dfrac{a^2}{b^2}\to\left(\dfrac{24}{25}\right)^2=\dfrac{24^2}{25^2}=\dfrac{(24)(24)}{(25)(25)}=\dfrac{576}{625}

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4 years ago
Sabrina is researching the growth of a population of horses on a ranch. She models the population of horses using the function b
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