Answer:
4.02g of Na2CO3⸱2H2O must be added completing the volume of the solution to 100mL
Explanation:
A 3%(w/v) solution contains 3g of solute (In this case, Na2CO3) in 100mL of solution.
Assuming we require 100mL of solution we must add 3g of Na2CO3. The reactant that is available is its dihydrate, with molar mass:
106g/mol + 2*MW H2O
106g/mol + 2*18g/mol = 142g/mol
That means the mass of Na2CO3.2H2O that must be added to prepare the solution is:
3g Na2CO3 * (142g/mol Na2CO3.2H2O / 106g/mol Na2CO3) =
<h3>4.02g of Na2CO3⸱2H2O must be added completing the volume of the solution to 100mL</h3>
PV=nRT
You are funding pressure and you have V = 9.45L, n = 1.9 moles, R = gas constant, and T = 228 K
P(9.45L) = (1.9moles)(0.0821)(228K)
Find P
Multiply
9.45P = 35.57
Divide
P = 3.76 L of N
Answer should be 3.76 liters of nitrogen
Answer:
Salt is a mineral/substance that is made up of sodium chloride. It is typically used as a food ingredient and a nutrient. There are different types of salt such as kosher salt, table salt, sea salt, smoked salt, etc.
Titration is the process by which the concentration of an unidentified analyte is found
Answer: The growth of the plant decides on the presence of plant hormone, auxin which develops in the roots and shoots. Auxins change the rate of elongation in plant cells, controlling how long they become. So, if the tips are removed, there is no auxin made and growth of the plant stops.
