Answer:
Zn(s) → Zn⁺²(aq) + 2e⁻
Explanation:
Let us consider the complete redox reaction:
Zn(s) + 2HCl(aq) → ZnCl₂(aq) + H₂(g)
This is a redox reaction because, both oxidation and reduction is simultaneously taking place.
- Oxidation (loss of electrons or increase in the oxidation state of entity)
- Reduction (gain of electrons or decrease in the oxidation state of the entity)
- An element undergoes oxidation or reduction in order to achieve a stable configuration. It can be an octet configuration. An octet configuration is that of outer shell configuration of noble gas.
Here Zn(s) is undergoing oxidation from OS 0 to +2
And H in HCl (aq) is undergoing reduction from OS +1 to 0.
Therefore, for this reaction;
Oxidation Half equation is:
Zn(s) → Zn⁺²(aq) + 2e⁻
Reduction Half equation is:
2H⁺ + 2e⁻ → H₂(g)
Answer:
The correct option is C
Explanation:
From the question we are told that
The reaction is
Generally 
Here 
is the change in enthalpy
is the change in the internal energy
is the difference between that number of moles of product and the number of moles of reactant
Looking at the reaction we can discover that the elements that was consumed and the element that was formed is 
and 
and this are both gases so the change would occur in the number of moles
So
![\Delta H = \Delta U + [16 -23]* RT](https://tex.z-dn.net/?f=%5CDelta%20%20H%20%20%3D%20%20%5CDelta%20%20U%20%2B%20%5B16%20-23%5D%2A%20%20RT)
The negative sign in the equation tell us that the enthalpy
would be less than the Internal energy 
Where are the following elements to choose from?
NaBrO3 is the chemical formula for Sodium Bromate.
Answer:
the cold one is going to have a faster reaction time
Explanation:
