Answer:
144 g of H₂O.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is given below:
CH₄ + 2O₂ —> CO₂ + 2H₂O
Next, we shall determine the mass of CH₄ that reacted and the mass of H₂O produced from the balanced equation. This can be obtained as follow:
Molar mass of CH₄ = 12 + (4×1)
= 12 + 4 = 16 g/mol
Mass of CH₄ from the balanced equation = 1 × 16 = 16 g
Molar mass of H₂O = (2×1) + 16
= 2 + 16 = 18 g/mol
Mass of H₂O from the balanced equation = 2 × 18 = 36 g
SUMMARY:
From the balanced equation above,
16 g of CH₄ reacted to produce 36 g of H₂O.
Finally, we shall determine the mass of H₂O produced by the reaction of 64 g of CH₄. This can be obtained as follow:
From the balanced equation above,
16 g of CH₄ reacted to produce 36 g of H₂O.
Therefore, 64 g of CH₄ will react to produce = (64 × 36)/16 = 144 g of H₂O.
Thus, 144 g of H₂O were obtained from the reaction.
