1) 3x+y+z=4
2) 2x+2y+3z=3
3) x+3y+2z = 5
1)*2 6x + 2y + 2z = 8
2) 2x + 2y +3z = 3
- __________________
4x - z = 5
2)*3 6x + 6y + 9z = 9
3)*2 2x + 6y + 4z = 10
- __________________
<span>4x+5z =-1
</span>
4x+5z = -1
4x - z =5
- ________
6z = -6
<u>z = -1
</u><u /><u>
</u>If z=-1,
4x -(-1) =5
4x = 5-1
x = 4/4
<u>x=1</u>
3x+y+z=4
3(1)+y+(-1)=4
3+y-1=4
<u>y=2
So z=-1, x=1, y=2</u>
45+10x the x stands for how many classes you take
Answer:
He would have to wait for 5 weeks
Step-by-step explanation:
$5 x $5 = $25
$25 + $10.50 = $35.50
Answer:
<em><u>x=-6, y=-2</u></em>, (As a point) (-6, -2).....The point form is not necessary unless you want to solve the system (of equations) by graphing.
Step-by-step explanation:
By substitution:
x-y=-4 By adding y on both sides,
x=y-4
Now you can substitute x for the expression (y-4)
Plug the (y-4) as x in the other equation.
So -2x+3y=6 becomes
-2(y-4)+3y=6
Now solve:
-2(y-4)+3y=6 distributes out to be
-2y+8+3y=6 Now combining like terms
y+8=6 Subtract 8 on both sides to isolate the variable
<u><em>y=-2</em></u>
Now plug the value -2 in where the y is in any equation (preferably the easier/less complicated one) and solve for x.
So x-y=-4 becomes
x-(-2)=-4
=x+2=-4
=<u><em>x=-6</em></u>
