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MAXImum [283]
3 years ago
5

What is the value of log Subscript 7 Baseline 343?

Mathematics
2 answers:
Aleks [24]3 years ago
6 0

Answer:

log_7(343)=3

Step-by-step explanation:

The value of log_7(343) can be easily obtained by recalling what the log notation means. Recall that logarithms are another way of writing exponents.

With the notation  log_7(343)=?  we want to find an exponent (logarithms are exponents). So read this expression as: what is the exponent we need to use on base "7" to get the number 343? That exponent is the answer to the question.

Equivalently in exponential form: What is the exponent "x" such that: 7^x=343. The answer to this is : "3" (the exponent 3 on base "7" renders 343)

"3" is the answer because  7^3=343

Yuliya22 [10]3 years ago
5 0

Answer:

the answer is 3

Step-by-step explanation:

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To rewrite in exponential form, the equation would be 5^?=625^x. From here, the bases need to be set equal. Since the fourth root of 625 is 5, the new equation becomes 625^1/4=625^x (625^1/4 is the same as the fourth root of 624). Now that the bases are the same, you can just solve for the variables, which become 1/4=x. Hope this helps :)
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Step-by-step explanation:

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2 years ago
Determine the values of \theta if sec\;\theta=-\frac{2}{\sqrt{3}}.
Masja [62]

Answer:

See below.

Step-by-step explanation:

So, we have:

\sec(\theta)=-2/\sqrt{3}

Recall that secant is simply the reciprocal of cosine. So we can:

\cos(\theta)=(\sec(\theta))^{-1}=(-2/\sqrt{3})^{-1}\\\cos(\theta)=-\sqrt{3}/2

Now, recall the unit circle. Since cosine is negative, it must be in Quadrants II and/or III. The numerator is the square root of 3. The denominator is 2. The whole thing is negative. Therefore, this means that 150 or 5π/6 is a candidate. Therefore, due to reference angles, 180+30=210 or 7π/6 is also a candidate.

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6 0
3 years ago
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Answer:

I'm sorry if i'm wrong but I hope this helps

Step-by-step explanation:

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Step-by-step explanation:

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