5^?=625^x, x=1/4
To rewrite in exponential form, the equation would be 5^?=625^x. From here, the bases need to be set equal. Since the fourth root of 625 is 5, the new equation becomes 625^1/4=625^x (625^1/4 is the same as the fourth root of 624). Now that the bases are the same, you can just solve for the variables, which become 1/4=x. Hope this helps :)
Answer:
False
Step-by-step explanation:
Answer:
See below.
Step-by-step explanation:
So, we have:

Recall that secant is simply the reciprocal of cosine. So we can:

Now, recall the unit circle. Since cosine is negative, it must be in Quadrants II and/or III. The numerator is the square root of 3. The denominator is 2. The whole thing is negative. Therefore, this means that 150 or 5π/6 is a candidate. Therefore, due to reference angles, 180+30=210 or 7π/6 is also a candidate.
Therefore, the possible values for theta is
5π/6 +2nπ
and
7π/6 + 2nπ
Answer:
I'm sorry if i'm wrong but I hope this helps
Step-by-step explanation:
Volume = l³ = 500
![length = \sqrt[3]{500} = 7.937m](https://tex.z-dn.net/?f=length%20%3D%20%20%5Csqrt%5B3%5D%7B500%7D%20%20%3D%207.937m)
Answer:
434
Step-by-step explanation:
multiply 62 and 7