We have a subtraction between two terms: h and 2g. Let's see the value of each term:
h is 4, it's already given.
2g means twice g, and g is 32. So, 2g is 64
So, the subtraction is
Determine the values of \theta if sec\;\theta=-\frac{2}{\sqrt{3}}.
1 answer:
Answer:
See below.
Step-by-step explanation:
So, we have:
Recall that secant is simply the reciprocal of cosine. So we can:
Now, recall the unit circle. Since cosine is negative, it must be in Quadrants II and/or III. The numerator is the square root of 3. The denominator is 2. The whole thing is negative. Therefore, this means that 150 or 5π/6 is a candidate. Therefore, due to reference angles, 180+30=210 or 7π/6 is also a candidate.
Therefore, the possible values for theta is
5π/6 +2nπ
and
7π/6 + 2nπ
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Answer:
Part A. I chose points (7,1.3) and (48,9.8)
Part B. a. Positive correlation; b. y = 0.21x - 0.2
Step-by-step explanation:
Part A.
I chose the first and last points on the line — (7 in, 1.3 lb) and (48 in, 9.8 lb).
That put three points on the line, three above it, and four below.
Part B
a. Type of correlation
There is a positive correlation between the length of a puppy and its weight.
You would expect a longer dog to be bigger and weigh more than a shorter dog.
b. The equation for the line of best fit
The slope-intercept equation for a straight line is
y = mx + b
where m is the slope of the line and b is the y-intercept.
The line passes through the points (7,1.3) and (48, 9.8).
(i) Calculate the slope of the line
\begin{array}{rcl}
The slope of the line is 0.21 lb/in.
(ii) Locate the y-intercept
Put the slope and the coordinates of one point into the slope-intercept formula.
The y-intercept is at (0,-0.2)
(iii) Write the equation for the line
y = 0.21x - 0.2
