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jasenka [17]
3 years ago
15

Can a linear function be continuous but not have a domain and range of all real numbers

Mathematics
1 answer:
ivolga24 [154]3 years ago
4 0
"Mathematically yes - but from an engineering point no. And micro black holes are very unstable. They will evaporate extremely violently" hope this helps
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The answer is x>−1/5 or x<1/5

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A line passes through the points (9, 30) and (18, 30). Which statement is true about the line?
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(9,30)(18,30)....when u have 2 sets of points and there y value is the same, then u have a horizontal line with a slope of 0

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Rationalise the denominator 10/root 2
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Multiply the numerator and denominator by √2
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Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.
Bad White [126]

Answer:

The final answers are x = 1 OR x = -3.

Step-by-step explanation:

Given the equation is x^2 -3 = -2x

Rewriting it in quadratic form as:- x^2 +2x -3 = 0.

a = 1, b = 2, c = -3.

Using Quadratic formula as follows:- x = ( -b ± √(b² -4ac) ) / (2a)

x = ( -2 ± √(4 -4*1*-3) ) / (2*1)

x = ( -2 ± √(4 +12) ) / (2)

x = ( -2 ± √(16) ) / (2)

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8 0
3 years ago
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Brady made a scale drawing of a rectangular swimming pool on a coordinate grid. The points (-20, 25), (30, 25), (30, -10) and (-
djverab [1.8K]

Answer:

Length = 50 units

width = 35 units

Step-by-step explanation:

Let A, B, C and D be the corner of the pools.

Given:

The points of the corners are.

A(x_{1}, y_{1}})=(-20, 25)

B(x_{2}, y_{2}})=(30, 25)

C(x_{3}, y_{3}})=(30, -10)

D(x_{4}, y_{4}})=(-20, -10)

We need to find the dimension of the pools.

Solution:

Using distance formula of the two points.

d(A,B)=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}----------(1)

For point AB

Substitute points A(30, 25) and B(30, 25) in above equation.

AB=\sqrt{(30-(-20))^{2}+(25-25)^{2}}

AB=\sqrt{(30+20)^{2}}

AB=\sqrt{(50)^{2}

AB = 50 units

Similarly for point BC

Substitute points B(-20, 25) and C(30, -10) in equation 1.

d(B,C)=\sqrt{(x_{3}-x_{2})^{2}+(y_{3}-y_{2})^{2}}

BC=\sqrt{(30-30)^{2}+((-10)-25)^{2}}

BC=\sqrt{(-35)^{2}}

BC = 35 units

Similarly for point DC

Substitute points D(-20, -10) and C(30, -10) in equation 1.

d(D,C)=\sqrt{(x_{3}-x_{4})^{2}+(y_{3}-y_{4})^{2}}

DC=\sqrt{(30-(-20))^{2}+(-10-(-10))^{2}}

DC=\sqrt{(30+20)^{2}}

DC=\sqrt{(50)^{2}}

DC = 50 units

Similarly for segment AD

Substitute points A(-20, 25) and D(-20, -10) in equation 1.

d(A,D)=\sqrt{(x_{4}-x_{1})^{2}+(y_{4}-y_{1})^{2}}

AD=\sqrt{(-20-(-20))^{2}+(-10-25)^{2}}

AD=\sqrt{(-20+20)^{2}+(-35)^{2}}

AD=\sqrt{(-35)^{2}}

AD = 35 units

Therefore, the dimension of the rectangular swimming pool are.

Length = 50 units

width = 35 units

7 0
3 years ago
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