The First Graph represents the situation.
The runner goes a lot of distance in a short amount of time (Demonstrated by the steep incline of the first portion). When the runner is tying their shoe, the distance remains the same, thus eliminating the second graph and the last graph because the last graph doesn't show the beginning of the problem. Finally, we know that the runner is slower after tying their shoe, this means the incline of the line would be far less as steep (Meaning the slope would be smaller). The only graph that depicts all of these, is the first one.
I Hope this Helps!
-Sinnamin
Answer:
7x^2 −12x−10
Step-by-step explanation:
((5x2 - 8x) + 1) + (2x2 - 4x - 11)
Factoring 7x2-12x-10
The first term is, 7x2 its coefficient is 7 .
The middle term is, -12x its coefficient is -12 .
The last term, "the constant", is -10
Step-1 : Multiply the coefficient of the first term by the constant 7 • -10 = -70
Step-2 : Find two factors of -70 whose sum equals the coefficient of the middle term, which is -12 .
-70 + 1 = -69
-35 + 2 = -33
-14 + 5 = -9
-10 + 7 = -3
-7 + 10 = 3
-5 + 14 = 9
-2 + 35 = 33
-1 + 70 = 69
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Answer:
8
Step-by-step explanation:
When you subtract the 9-1=8
Answer:
1595 ft^2
Step-by-step explanation:
The answer is obtained by adding the areas of sectors of several circles.
1. Think of the rope being vertical going up from the corner where it is tied. It goes up along the 10-ft side. Now think of the length of the rope being a radius of a circle, rotate it counterclockwise until it is horizontal and is on top of the bottom 20-ft side. That area is 3/4 of a circle of radius 24.5 ft.
2. With the rope in this position, along the bottom 20-ft side, 4.5 ft of the rope stick out the right side of the barn. That amount if rope allows for a 1/4 circle of 4.5-ft radius on the right side of the barn.
3. With the rope in the position of 1. above, vertical and along the 10-ft left side, 14.5 ft of rope extend past the barn's 10-ft left wall. That extra 14.5 ft of rope are now the radius of a 1/4 circle along the upper 20-ft wall.
The area is the sum of the areas described above in numbers 1., 2., and 3.
total area = area 1 + area 2 + area 3
area of circle = (pi)r^2
total area = 3/4 * (pi)(24.5 ft)^2 + 1/4 * (pi)(4.5 ft)^2 + 1/4 * (pi)(14.5 ft)^2
total area = 1414.31 ft^2 + 15.90 ft^2 + 165.13 ft^2
total area = 1595.34 ft^2
