Answer:
x = -2, y = -2
Step-by-step explanation:
Your goal is to try and cancel out a variable. I want to get rid of y so i subtracted the first equation from the second one.
After that I solve for x and got x=-2.
I used x=-2 and plugged it back into either of the equation to solve for y.
Answer:
a=50
Step-by-step explanation:
a + 2a + 30 = 180
3a + 30 = 180
(-150 from both sides)
3a = 150
(Divide by 3 from both sides)
a = 50
The ratio is 4:5
Divide both terms by 4
16/4 =4
20/4=5
Hello from MrBillDoesMath!
Answer:
11
Discussion:
Let "n" be the smaller number. Then
n * (n+5) = 176.
My first reaction to this problem was to factor 176 in my head. That's 176 = 16 * 11 and 16 is 5 more than 11. So that's the solution!.... Now let's solve it using the brute force approach:
n(n+5) = 176 =>
n^2 + 5n - 176 = 0 => use the quadratic formula
n = ( -5 +\- sqrt( 5^2 - 4(1)(-176)) ) /2
= ( -5 +\- sqrt( 25 + 704) )/ 2
= ( -5 +\- sqrt (729) ) /2 => as sqrt(729) = 27
= (-5 +\- 27) / 2 =>
= (-5 + 27)/2 or ( -5 -27)/2 =>
= 22/2 or -32/2 =>
= 11 or -16
But -16 is not allowed as the question wants a positive value.
Thank you,
MrB
Answer:
1. sum of term = 465
2. nth term of the AP = 30n - 10
Step-by-step explanation:
1. The sum of all natural number from 1 to 30 can be computed as follows. The first term a = 1 and the common difference d = 1 . Therefore
sum of term = n/2(a + l)
where
a = 1
l = last term = 30
n = number of term
sum of term = 30/2(1 + 30)
sum of term = 15(31)
sum of term = 465
2.The nth term of the sequence can be gotten below. The sequence is 20, 50, 80 ......
The first term which is a is equals to 20. The common difference is 50 - 20 or 80 - 50 = 30. Therefore;
a = 20
d = 30
nth term of an AP = a + (n - 1)d
nth term of an AP = 20 + (n - 1)30
nth term of an AP = 20 + 30n - 30
nth term of the AP = 30n - 10
The nth term formula can be used to find the next term progressively. where n = number of term
The sequence will be 20, 50, 80, 110, 140, 170, 200..............
