Answer:
Solve by factoring.
1. 2x^2+9x+26=-4x+5
2x²+9x+4x+26-5=0
2x²+13x+21=0
doing middle term factorization
2x²+7x+6x+21=0
x(2x+7)+3(2x+7)=0
<u>(</u><u>2</u><u>x</u><u>+</u><u>7</u><u>)</u><u>(</u><u>x</u><u>+</u><u>3</u><u>)</u><u>=</u><u>0</u>
<u>either</u>
<u>x</u><u>=</u><u>-</u><u>7</u><u>/</u><u>2</u>
<u>or</u>
<u>x</u><u>=</u><u>-</u><u>3</u><u>.</u>
2.
3x^2-6x-4=0
comparing above equation with ax²+bx+c=0
we get
a=3
b=-6
c=-4
By using quadratic equation
x=
Substituting value
x=
x=
x=
-8x=6±2√21
taking positive
-8x=6+2√21
x=
x=-
taking negative
-8x=6-2√21
x=
x=-
Answer:
139118
Step-by-step explanation:
Answer:
That is the answer step by step in exponents hope that helped