The answer is (1,3)
I hope it helped u
The Answer is: This Not SAS
This kind of problem request the use of harmonic mean:
if t₁ is the Time spent by Jessica, and
t₂, the time spent by Felecia, and t₃ the time spent by both, then the equation of that kind of problem will be:
1/t₁ + 1/t₂ =1/t₃.
t₁ = 1h45 min, t₂ (unknown, to be calculated), t₃ = 1 h, to ease things let' convert the time in minutes
t₁ = 105 min
t₂ = ?(time needed to Felicia to maw the lawn)
t₃ = 60 min
1/105 +1/t₂ = 1/60===> 1/t₂ = 1/60 - 1/105==> 1/t₂ =1/140
& t₂ =140 minutes or t₂ = 2h & 20 min
1) 5r*7/15 = 35r/15 = 7r/3
2) 1.2 (w + u/12) = 1.2w + 0.1u
3) 0.2w/2 = 0.1w
4) x +3x/4 + 0.9z = 1.75x + 0.9z
5) 4*( 3y/8 - x/2) = 1.5y -2x
6) 0.6* ( 4w/6 - 5v/18 ) = 2w/5 - 5v/3