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Tatiana [17]
3 years ago
10

Use linear combination. To solve system -2x+7y=10 X-3y=-3

Mathematics
2 answers:
Musya8 [376]3 years ago
6 0
So
use elimintation
multily second equation by 2
2x-6y=-6
add to first equation

2x-2x+7y-6y=10-6
y=4
subsitute
x-3(4)=-3
x-12=-3
add 12 to both sdies
x=9


x=9
y=4
Tamiku [17]3 years ago
3 0
-2x + 7y = 10 ⇒ -2x + 7y = 10
   x - 3y = -3   ⇒ <u>-2x + 6y = 6  </u>
                                      y = 4
                         -2x + 7(4) = 10
                           -2x + 28 = 10
                          <u>         -28   -28</u>
                                   <u>-2x</u> = <u>-18</u>
                                    -2      -2
                                       x = 9
                                  (x, y) = (9, 4)
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Answer:

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Step-by-step explanation:

y = 9x + 7

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y = (x-7)/9

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Pleas help me find the answer and show the work to this question
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Answer:

Leg\ 1 = 8

Leg\ 2 = 15

Step-by-step explanation:

Given: See Attachment

Required

Determine the length of the legs

To do this, we apply Pythagoras theorem.

Hyp^2 = Adj^2 + Opp^2

In this case:

17^2 = x^2 + (2x- 1)^2

Open Bracket

17^2 = x^2 + 4x^2- 2x-2x + 1

17^2 = 5x^2 - 4x + 1

289= 5x^2 - 4x + 1

Collect Like Terms

5x^2 - 4x + 1 - 289 = 0

5x^2 - 4x - 288 = 0

Solving using quadratic formula:

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So:

x = 8 or x = -7.2

Since, x can't be negative, then:

x = 8

One of the leg is:

Leg\ 1 = x

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Leg\ 2 = 2x - 1

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6 0
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Darina [25.2K]

Answer:

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Step-by-step explanation:

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m = ( y2-y1)/(x2-x1)

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sleet_krkn [62]

Answer:

There is no point of the form (-1, y) on the curve where the tangent is horizontal

Step-by-step explanation:

Notice that when x = - 1. then dy/dx becomes:

dy/dx= (y+2) / (2y+1)

therefore, to request that the tangent is horizontal we ask for the y values that make dy/dx equal to ZERO:

0 = ( y + 2) / (2 y + 1)

And we obtain y = -2 as the answer.

But if we try the point (-1, -2) in the original equation, we find that it DOESN'T belong to the curve because it doesn't satisfy the equation as shown below:

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