Answer:
Part 1
Given equation:
C(t) = -0.30 (t – 12)² + 40
For t = 0
C(t) = -0.30 (0 - 12)² + 40
C(t) = -0.30 (-12)² + 40
C(t) = -3.2
For t = 12 (noon)
C(t) = -0.30 (12 - 12)² + 40
C(t) = -0.30 (0)² + 40
C(t) = 40
For t = 24 (midnight)
C(t) = -0.30 (24 - 12)² + 40
C(t) = -0.30 (12)² + 40
C(t) = -0.30 × 144 + 40
C(t) = - 43.2 + 40
C(t) = -3.2
Part 2
attached below
Part 3
C(t) = –0.30(t – 12)² + 40
F(t)=9/5C(t)+32
Substituting the values:
F(t)=9/5{–0.30 (t – 12)² + 40}+32
F(t) = -0.54 (t – 12)² + 72 + 32
F(t) = -0.54 (t – 12)² + 104
5, 6 and 7, should be simplish
good luck, i hope this helps :)
Step-by-step explanation:
The total perimeter is 3x +21= ? first we isolate the variable by subtracting 21 on both sides. we then get 3x=21 now we divide by three on both sides and we find that x=7 to check this plug this in to x+9 x+10 and x +2 and see if x+10 is the hypotenuse.
<span>2b</span>²<span> - 3b + 4a</span>² =
2*(8)² - 3*8 + 4*(-6)² =
2 * 64 - 24 + 4*36 =
128 - 24 + 144 = 248
