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saul85 [17]
3 years ago
6

Yearly travel expenses for a family of four are normally distributed with a mean expense equal to $3,000 and a standard deviatio

n equal to $500. What is the probability of travel expenses being greater than $4,000?
Mathematics
1 answer:
Scrat [10]3 years ago
3 0

Answer:

The probability is 0.02275

Step-by-step explanation:

We shall first find the z-score here

z-score = (x -mean)/SD

from the question;

x = 4,000

mean = 3,000

SD = 500

z-score = (4,000-3,000)/500 = 1000/500 = 2

So the probability we want to calculate is;

P(z > 2) = 0.02275

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Answer:

Last Option

Step-by-step explanation:

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Where

c = 14\\a = 11\\b = 19

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6 0
3 years ago
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vodomira [7]

Answer:

10 strawberries

Step-by-step explanation:

If Mike can pick 50 strawberries in 5 minutes then it is safe to assume that for 1 minute, Mike can pick 10 strawberries since you divide 50 by 5 in which Mike can pick a strawberry for every 6 seconds.

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3 years ago
-10t+8+-2t=16<br> I need help!
Nutka1998 [239]

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there are two answers

Step-by-step explanation:

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4 years ago
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Please show the rest of the question if there is any

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You make $25000 a year, and you get a 10% raise. Your new salary is $____ The next year you get a 10% cut. Your new salary is $_
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Firstly, we have to find out what 10% of $25000 is. To do this, multiply $25000 by 0.1 (10% in decimal form): \$25000 \times 0.1=\$2500 . <em>$2500 is the 10% raise.</em>

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