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musickatia [10]
1 year ago
5

SinA=√1-x÷√1+X Find the value of cosA

Mathematics
1 answer:
Irina-Kira [14]1 year ago
6 0

The value of cos A is √(1 + x²)/ (1 - x²) /√1 + x

<h3>Trigonometric ratios</h3>

It is important to note that

sin A = opposite/ hypotenuse

cos A = adjacent/ hypotenuse

Then,

opposite = \sqrt{1} - x

Hypotenuse = \sqrt{1} + x

Let's find the adjacent side using the Pythagorean theroem

(\sqrt{1} + x)^2 = (\sqrt{1 -x } )^2 + x^2

1 + x^2 = 1 - x^2 + x^2

x = \sqrt{\frac{1 + x^2}{1 -x^2} }

cos A = x/hypotenuse

cos A = \frac{\sqrt{\frac{1+x^2}{1 -x^2} } }{\sqrt{1} +x}

cos A = √(1 + x²)/ (1 - x²) /√1 + x

Thus, the value of cos A is √(1 + x²)/ (1 - x²) /√1 + x

Learn more about trigonometric identities here:

brainly.com/question/7331447

#SPJ1

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Answer:

j=12

Step-by-step explanation:

we know that

In a join variation, If j varies jointly with respect to g and v, the equation will be of the form j = kgv

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we have

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substitute and solve for k

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The equation is equal to

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Find the value of j when g=8,v=9

substitute the values in the equation and solve for j

j=\frac{1}{6}(8)(9)

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Kira ran 8 1/5 miles in 69 7/10 minutes. What is Kira’s average time per mile?
Setler79 [48]

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1 mile = 8.5 minutes

Step-by-step explanation:

<u>Determining the equation:</u>

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