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Luden [163]
3 years ago
8

What is the solution of this equation? 1/3y = -7

Mathematics
1 answer:
Alex777 [14]3 years ago
3 0
   1/3y = -7
3(1/3y = -7)
        y = -21

Hope this helps.
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If the figure below are similar with a scale factor of 2:3, find the value of x.
ahrayia [7]

Answer x=63

Step-by-step explanation:

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3 years ago
Solve for x: −2x − 4 > 8
Pavlova-9 [17]
To solve for x in an inequality is very similar to solving for x in an equation since for both you would need to isolate x. 

step 1) -2x-4>8               add the 4 over to move any constants over to the                         +4 +4              other side.
             -2x> 12

step 2) x< -6                 Divide out the -2 to isolate x, however, keep in mind,                                      when you divide or multiply over any negative                                                   number, you must also remember to flip the inquality                                      sign.


Answer: x<-6
6 0
3 years ago
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Which word describes the slope of the line?<br><br> positive<br> negative<br> zero<br> undefined
FrozenT [24]

Answer:

Negative

Step-by-step explanation:

the slope in this equation is negetive as it is pointing in a downwards position.

Zero would be horizontal, undefined would be vertical and positive would be going in an upwards motion

7 0
2 years ago
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Write an equation for an ellipse centered at the origin, which has foci at (\pm\sqrt{8},0)(± 8 ​ ,0)(, plus minus, square root o
Alchen [17]

Answer:

The equation of ellipse centered at the origin

\frac{x^2}{18} +\frac{y^2}{10} =1

Step-by-step explanation:

given the foci of ellipse (±√8,0) and c0-vertices are (0,±√10)

The foci are (-C,0) and (C ,0)

Given data (±√8,0)  

the focus has x-coordinates so the focus is  lie on x- axis.

The major axis also lie on x-axis

The minor axis lies on y-axis so c0-vertices are (0,±√10)

given focus C = ae = √8

Given co-vertices ( minor axis) (0,±b) = (0,±√10)

b= √10

The relation between the focus and semi major axes and semi minor axes are c^2=a^2-b^2

      a^{2} = c^{2} +b^{2}

a^{2} = (\sqrt{8} )^{2} +(\sqrt{10} )^{2}

a^{2} =18

a=\sqrt{18}

The equation of ellipse formula

\frac{x^2}{a^2} +\frac{y^2}{b^2} =1

we know that a=\sqrt{18} and b=\sqrt{10}

<u>Final answer:</u>-

<u>The equation of ellipse centered at the origin</u>

<u />\frac{x^2}{18} +\frac{y^2}{10} =1<u />

                                   

8 0
3 years ago
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Answer:

hsuaiabshsisnsbkjwnsjns

Step-by-step explanation:

1828392919287382928whshsisnsjjs

sorry, i can't answer that question

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