1. Check the drawing of the rhombus ABCD in the picture attached.
2. m(CDA)=60°, and AC and BD be the diagonals and let their intersection point be O.
3. The diagonals:
i) bisect the angles so m(ODC)=60°/2=30°
ii) are perpendicular to each other, so m(DOC)=90°
4. In a right triangle, the length of the side opposite to the 30° angle is half of the hypothenuse, so OC=3 in.
5. By the pythagorean theorem,

6. The 4 triangles formed by the diagonal are congruent, so the area of the rhombus ABCD = 4 Area (triangle DOC)=4*

=

(

)
To find the value of r
We will follow the steps below
Usinf the equation of a slope:
slope(m) =

from the question given;
m= -3/4
x₁ = 3
y₁=4
x₂=-1
y₂=r
substituting the values into the slope formula

we can now simplify and then solve for r

cross-multiply
-3 x -4 = 4(r-4)
12 = 4(r-4)
Divide both-side of the equation by 4

3 = r - 4
add 4 to both-side of the equation
3+4 = r-4+4
7 = r
r=7
Therefore the value of r is 7
Answer:
x=59
Step-by-step explanation:
The zeros are the x-intercepts, which are -2 and 4.
The axis of symmetry is x = 1
The vertex of the graph is (1,9)
The answer is 2 11/12 because you do 3 1/3 + -2 1/4 which gets you 1 1/2. Then you need to add 1 5/6 to the 1 5/6 to get your answer. So when you add up your answer you get 2 11/12. Hope this helps.