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Softa [21]
2 years ago
7

Amy rolls a number cube ten times and gets 3 four times! If she rolls the number cube 240 times, how many times should she get a

3 (Hint: Should her results be used, or the theoretical probability?).
Mathematics
1 answer:
Iteru [2.4K]2 years ago
7 0

Answer:

Amy should not use her previous luck of rolling a 3 four times because theoretical probability remains the same even after an event favoring one side has occurred by chance.

Step-by-step explanation:

Assuming that this number cube has 6 sides, there is only 1 side that has a 3 on it. For this reason, every time the cube is rolled there is a 1 in 6 chance that the number will be a 3. If she rolls the number cube 240 times, 1 out of 6 rolls would be a 3. This means that 240/6 equals the number of times she would get a 3. Moreover, Amy would role the number 3 on 40 different times after rolling the cube for a total of 240.

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The formula F = 1.8C + 32 allows you to find the Fahrenheit (F) temperature for a given Celsius (C) temperature. Solve the equat
Slav-nsk [51]

Answer:

The formula to calculate the Celsius temperature for a given Fahrenheit temperature is:

C=\frac{F-32}{1.8}

Step-by-step explanation:

Given formula:

F=1.8C+32

where F represents temperature in Fahrenheit and C represents  temperature in Celsius.

To solve the equation for C.

Solution:

We have,

F=1.8C+32

Subtracting both sides by 32.

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F-32=1.8C

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Please help?!
Anton [14]

Answer:

Δ PQT ~ Δ QRS  .....{S-S-S test for similarity}...Proof is below.

Step-by-step explanation:

Given:

In Δ PQT

PQ = 30 ft

QT = 28 ft

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In Δ QRS

QR = 15 ft

RS = 14 ft

SQ = 10 ft

To Prove:

Δ PQT ~ Δ QRS

Proof:

First we consider  the ratio of the sides

\frac{PQ}{QR}=\frac{30}{15} = \frac{2}{1}            ..............( 1 )

\frac{QT}{RS}=\frac{28}{14} = \frac{2}{1}            ..............( 2 )

\frac{TP}{SQ}=\frac{20}{10} = \frac{2}{1}            ..............( 3 )

So By equation ( 1 ), ( 2 ) and  ( 3 ) we get

\frac{PQ}{QR}=\frac{QT}{RS} = \frac{TP}{SQ}

Now in Δ PQT  and Δ QRS we have

\frac{PQ}{QR}=\frac{QT}{RS} = \frac{TP}{SQ}

Which are corresponding sides of a similar triangle in proportion.

∴ Δ PQT ~ Δ QRS  .....{S-S-S test for similarity}...Proved

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