Using the z-distribution, it is found that the 95% confidence interval is (0.46, 0.526), and it does not provide strong evidence against that belief.
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:
In which:
is the sample proportion.
In this problem, we have a 95% confidence level, hence
, z is the value of Z that has a p-value of 
, so the critical value is z = 1.96.
We have that a random sample of 864 births in a state included 426 boys, hence the parameters are given by:
Then, the bounds of the interval are given by:
The 95% confidence interval estimate of the proportion of boys in all births is (0.46, 0.526). Since the interval contains 0.506, it does not provide strong evidence against that belief.
More can be learned about the z-distribution at brainly.com/question/25890103
C ,in the most parenthesis
Answer:
227750
Step-by-step explanation:
If we assume that the rate of increase in population is linear, then in 4 years the increase in population is (224000 - 221000) = 3000.
So, the rate of increase in population is 
persons per year.
Now, we have to calculate the population of the town after an additional 5 years.
So, the population in 5 years will increase by (750 × 5) = 3750
Therefore, the population after an additional 5 years will be (224000 + 3750) = 227750. (Answer)
Answer: 40%
Step-by-step explanation: The total number of pizzas is 12 + 18 = 30. Mitchel bought 12 of those 30 pizzas. To find the percentage you do the portion/total. Thus 12/30 = 0.4, as a proportion. To turn a proportion into a percentage simply multiply by 100. 0.4 * 100 = 40%
What is the difference between multicellular and unicellular?
