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Rudik [331]
3 years ago
13

Two glasses of milk and three snack bars have a total of 72 carbs. and 4 glasses of milk and 2 snack bars have a total of 88 car

bs. Determine how many carbs are one glass of mild and one snack bar.
Mathematics
1 answer:
melisa1 [442]3 years ago
7 0

Answer:

one glass of milk = 15 carbs

one bar = 14 carbs

Step-by-step explanation:

let 'm' = one glass of milk

let 'b' = one snack bar

system of equations:

2m + 3b = 72

4m + 2b = 88

I used the elimination method and multiplied the 1st equation by -2

  -4m - 6b = -144

+  <u>4m + 2b =  88</u>

           -4b = -56

              b = 14

now solve for 'm'

2m + 3(14) = 72

2m + 42 = 72

2m = 30

m = 15

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Answer:

discriminant is zero (0)

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Actually, you have a double root here:  {6, 6}:  "two real, equal roots."  That tells us immediately that the value of the discriminant was zero (0).

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A supermarket employee is making a mixture of cashews and almonds. Cashews cost $7 per pound, and almonds cost $5 per pound. The
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Step-by-step explanation:

It has to be less than 6 ,  x+y<6

Now in inequalities that have 7 and 5 in them, 7 represents the cost of first ingredient and 5 the cost of second ingredient.multiply each of that number with quantity of that ingredient and sum both up we get the price of the mixture.

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4 0
3 years ago
1) Miguel has a gift card to an electronics store. He has $ 150 on the card. He purchased a DVD for $ 20 and some games for $12.
GrogVix [38]

Answer:

9 games

Step-by-step explanation:

If he purchase 1 game, he spent $12.50. If he purchased 2 games, he spent 2(12.50) = $25.

This means he spent 12.5x for x number of games.

His total spending will be 12.5x + 20. He has $17.50 left on the card from $150.

150 - (12.5x + 20) = 17.5

150 - 12.5x -20 = 17.5

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8 0
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In how many ways can a quality-control engineer select a sample of3 transistors for testing frm a batch of 100 transistors?
Advocard [28]

Answer:

161700 ways.

Step-by-step explanation:

The order in which the transistors are chosen is not important. This means that we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

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6 0
3 years ago
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