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3 years ago

Choose the correct simplification of the expression (3x − 6)(2x2 − 4x − 5).

2 answers:

8 0

(3x×2x^2)+(3x×-4x)+(3x×-5)+(-6×2x^2)+(-6×-4x)+(-6×-5)
so, (6x^3)+(-12x^2)+(-15x)+(-12x^2)+(24x)+(30)

-12x^2can be added to the other -12x^2, which is =-24x^2
same thing with -15x and 24x that =9x

final answer
6x^3-24x^2+9x+30

lukranit [14]3 years ago

4 0

Answer:

The correct option is C. 6x³ - 24x² + 9x + 30

Step-by-step explanation:

The equation which is to be simplified :

(3x − 6)(2x² − 4x − 5)

Now, to simplify using the distributive law of multiplication over addition

⇒ 3x(2x² − 4x − 5) - 6(2x² − 4x − 5)

Again, By distributive law, we have :

⇒ 6x³ - 12x² - 15x - 12x² + 24x + 30

⇒ 6x³ - 12x² - 12x² - 15x + 24x + 30

⇒ 6x³ - 24x² + 9x + 30

Hence, The correct option is C. 6x³ - 24x² + 9x + 30

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Quadratic function and equation

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Answer:

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Step-by-step explanation:

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4 years ago

What is the volume of a square pyramid with a base length of 6cm and a height of 9cm?

emmainna [20.7K]

Answer:
Volume = 108 cm ³

Explanation:
For a square pyramid, the volume can be calculated as follows:
Volume = $\frac{1}{3}$ * area of base * height
Volume = $\frac{1}{3}$ * side² * height
We have:
side length = 6 cm
height = 9 cm
Therefore:
Volume = $\frac{1}{3}$ * 36 * 9 = 108 cm ³

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4 years ago

Mr. Indigo purchased some trees to plant in his backyard. He bought three oak trees for $23 each and an elm tree for $42. What w

Rom4ik [11]

Answer:

Total cost = $111

Step-by-step explanation:

Given:

Total number of oak tree = 3

Total number of elm tree = 1

Each oak tree cost = $23

Each elm tree cost = $42

Find:

Total cost

Computation:

Total cost = 3[Each oak tree cost] + 1[Each elm tree cost]

Total cost = 3[23] + 1[42]

Total cost = 69 + 42

Total cost = $111

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3 years ago

Need answers right now <br> tysm

EastWind [94]

If the three vertices of the rhombus are W(2,5),x(6,3),Y(2,1) then the area of the rhombus is 16 square units.

Given the three vertices of the rhombus are W(2,5),x(6,3),Y(2,1).

We are required to find the area of the rhombus when the fourth point Z is plotted.

We have to plot the points of the rhombus in the graph. We know that all the sides of the rhombus should be equal to each other. So by adjusting the blocks in the graph we will be able to plot Z as (-2,3).

In this way the diagonals are ZX and WY.

ZX= $\sqrt{(3-3)^{2} +(6+2)^{2} }$