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marishachu [46]
4 years ago
14

Round 6,212 to the nearest hundred

Mathematics
2 answers:
jeka57 [31]4 years ago
6 0

Your answer will be 6,200.

masya89 [10]4 years ago
3 0

Answer:


Step-by-step explanation:

6,212 яσυи∂є∂ тσ тнє иєαяєѕт нυи∂яє∂ ιѕ


6,200


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Randy can buy 6 gallons of gas for $18 or 7 gallons of gas for $21. how much do you think he would pay for 8 gallons of gas?
lesantik [10]

18/6 = 3 dollars per gallon

8 x 3 = 24

 8 gallons would cost $24

answer is C

6 0
3 years ago
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Could I get some help on this?
Monica [59]

Answer:

200.5ft²

Step-by-step explanation:

According to my calculation this is the answer ..

4 0
2 years ago
Solve the following system of equations graphically. y - 4 = 0 2x - y - 2 = 0 What is the solution set?
tatiyna

Answer:

{(x,y)|(x=3,y=4)}

Step-by-step explanation:

The given system of equations is;

y-4=0...(1)

and

2x-y-2=0...(2)

We rewrite the equations in the standard form to get:

y=4...(3)

2x-y=2...(4)

We now substitute equation (3) into equation (4) to get:

2x-4=2

Group similar terms:

2x=2+4

2x=6

Divide both sides by 2

\frac{2x}{2}=\frac{6}{2}

This implies that:

x=3

Therefore the solution set is:

{(x,y)|(x=3,y=4)}

7 0
3 years ago
In a class 27 of students, 12 have a cat and 11 have a dog. There are 5 students who have a cat and a dog. What is the probabili
frosja888 [35]

Answer:

41.67% probability that a student has a dog given that they have a cat

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: having a cat.

Event B: having a dog.

12 of 27 students have a cat:

This means that P(A) = \frac{12}{27}

5 students who have a cat and a dog.

This means that P(A \cap B) = \frac{5}{27}

What is the probability that a student has a dog given that they have a cat?

P(B|A) = \frac{\frac{5}{27}}{\frac{12}{27}} = \frac{5}{12} = 0.4167

41.67% probability that a student has a dog given that they have a cat

6 0
4 years ago
One bar of candy A and two bars of candy B have 777 calories. Two bars of candy A and one bar of candy B contain 783 calories. F
RSB [31]

Answer:

A has 263 calories

B has 257 calories

Step-by-step explanation:

system of equations:

a + 2b = 777

2a + b = 783

I multiplied the first equation by -2 to eliminate the 'a' terms

  -2a - 4b = -1554

+ <u> 2a  + b =    783</u>

         -3b = -771

b = 257

solve for 'a'

a + 2(257) = 777

a + 514 = 777

a = 263

4 0
3 years ago
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