Less then.. The first two numbers before the decimal are the same 95. After the decimal is where you'll see the change. Your first number is .045 and the second one is .545.. "0," is less than "5."
5 x 10 is 50 then 50 + 11 is 61 so I think it would be 61 ;)
Answer:
The factors of x^2+3x-4 are (x-1)(x+4) ....
Step-by-step explanation:
We have to find the factors of x^2+3x-4
As we know that this is a quadratic equation.
So we have to find the roots first.
The roots are -1 and 4.
Now completing the quadratic formula using the roots we have :
x^2+4x-x-4
Make a pair of first two terms and last two terms:
(x^2+4x)-(x+4)
Now take out the common from each pair:
x(x+4)-1(x+4)
(x-1)(x+4)
Thus the factors of x^2+3x-4 are (x-1)(x+4) ....
I cant read the letters but the bottom left is nonlinear
For this case we have the following expression:
Let's evaluate the expression for some values of x.
We have then:
For x = 1:
For x = 2:
For x = 3:
For x = 4:
For x = 5:
Answer:
The value of the expression in ordered pairs is:
- (1,8)
- (2.6)
- (3,4)
- (4.2)
- (5.0)
