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Nookie1986 [14]
3 years ago
5

Miss Taylor graded 50 English research papers. Twelve of them received a grade of A. Miss Taylor drew a circle graph to display

the grades. What percent of the circle graph was devoted to the A papers?
Mathematics
1 answer:
nikdorinn [45]3 years ago
3 0
<h3>Answer:</h3>

\large\boxed{24\%}

<h3>Step-by-step explanation:</h3>

In this question, it's asking you to find how much percentage the circle graph is for "A" papers.

To solve this question, we would need to use information from the question.

Important information:

  • Graded 50 English research papers
  • 12 of those papers had an "A" grade

With the information above, we can solve the question.

We know that there are 12 research papers that received an A and there are 50 research papers in total.

We would divide 12 by 50 in order to find the percentage of the papers that got an A.

12\div50=24

When you divide, you should get 24.

This means that 24% of the circle graph is devoted to "A" papers.

<h3>I hope this helped you out.</h3><h3>Good luck on your academics.</h3><h3>Have a fantastic day!</h3>
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Answer:

48.75$

Step-by-step explanation:

the difference is  about 16.25$

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Match the parabolas represented by the equations with their vertices. y = x2 + 6x + 8 y = 2x2 + 16x + 28 y = -x2 + 5x + 14 y = -
GaryK [48]

Consider all parabolas:

1.

y = x^2 + 6x + 8,\\y=x^2+6x+9-9+8,\\y=(x^2+6x+9)-1,\\y=(x+3)^2-1.

When x=-3, y=-1, then the point (-3,-1) is vertex of this first parabola.

2.

y = 2x^2 + 16x + 28=2(x^2+8x+14),\\y=2(x^2+8x+16-16+14),\\y=2((x^2+8x+16)-16+14),\\y=2((x+4)^2-2)=2(x+4)^2-4.

When x=-4, y=-4, then the point (-4,-4) is vertex of this second parabola.

3.

y =-x^2 + 5x + 14=-(x^2-5x-14),\\y=-(x^2-5x+\dfrac{25}{4}-\dfrac{25}{4}-14),\\y=-((x^2-5x+\dfrac{25}{4})-\dfrac{25}{4}-14),\\y=-((x-\dfrac{5}{2})^2-\dfrac{81}{4})=-(x-\dfrac{5}{2})^2+\dfrac{81}{4}.

When x=2.5, y=20.25, then the point (2.5,20.25) is vertex of this third parabola.

4.

y =-x^2 + 7x + 7=-(x^2-7x-7),\\y=-(x^2-7x+\dfrac{49}{4}-\dfrac{49}{4}-7),\\y=-((x^2-7x+\dfrac{49}{4})-\dfrac{49}{4}-7),\\y=-((x-\dfrac{7}{2})^2-\dfrac{77}{4})=-(x-\dfrac{7}{2})^2+\dfrac{77}{4}.

When x=3.5, y=19.25, then the point (3.5,19.25) is vertex of this fourth parabola.

5.

y =2x^2 + 7x +5=2(x^2+\dfrac{7}{2}x+\dfrac{5}{2}),\\y=2(x^2+\dfrac{7}{2}x+\dfrac{49}{16}-\dfrac{49}{16}+\dfrac{5}{2}),\\y=2((x^2+\dfrac{7}{2}x+\dfrac{49}{16})-\dfrac{49}{16}+\dfrac{5}{2}),\\y=2((x+\dfrac{7}{4})^2-\dfrac{9}{16})=2(x+\dfrac{7}{4})^2-\dfrac{9}{8}.

When x=-1.75, y=-1.125, then the point (-1.75,-1.125) is vertex of this fifth parabola.

6.

y =-2x^2 + 8x +5=-2(x^2-4x-\dfrac{5}{2}),\\y=-2(x^2-4x+4-4-\dfrac{5}{2}),\\y=-2((x^2-4x+4)-4-\dfrac{5}{2}),\\y=-2((x-2)^2-\dfrac{13}{2})=-2(x-2)^2+13.

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

There are 12 marbles in total. There are 4 yellow marbles. Therefore there is a 4/12 probability of Randomly picking a Yellow marble the first time . Since she placed the marble back, there is a 4/12 probability of getting a yellow marble the 2nd time.

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Answer:

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Step-by-step explanation:

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2nd Part:

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3 0
3 years ago
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