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nasty-shy [4]
2 years ago
8

Human visual inspection of solder joints on printed circuit boards can be very subjective. Part of the problem stems from the nu

merous types of solder defects (e.g., pad non-wetting, knee visibility, voids) and even the degree to which a joint possesses one or more of these defects. Consequently, even highly trained inspectors can disagree on the disposition of a particular joint. In one batch of 10,000 joints, inspector A found 728 that were judged defective, inspector B found 744 such joints, and 1365 of the joints were judged defective by at least one of the inspectors. Suppose that one of the 10,000 joints is randomly selected.a. What is the probability that the selected joint was judged to be defective by neither of the two inspectors?b. What is the probability that the selected joint was judged to be defective by inspector B but not by inspector A?
Mathematics
1 answer:
Basile [38]2 years ago
6 0

Answer:

a) 0.8841

b) 0.0435

Step-by-step explanation:

A : the set of joints deemed defective by inspector A.

B: the set of joints deemed defective by inspector B.

U: the set of all joints.

The problem says |A|=724, |B|=751, |A∪B|=1159, |U|=10000. Hence, with the help of Venn diagram we can answer the following:

Part a)

This asks for the number of joints that are ∉(A∪B).

hence,

P (∉(A∪B)) :

\frac{10000-1159}{10000} \\\\=0.8841

part b)

This asks for the number of joints that are in B but not in A, which Is represented as the set B−A

= \frac{|B| - |AandB| }{|U|}\\\\=  \frac{751-316 }{10000}\\\\= 0.0435

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Solve x2 - 8x = 20 by completing the square. Which is the solution set of the equation?
Artyom0805 [142]

Answer:

{-2,10}

Step-by-step explanation:

x^2 - 8x = 20

Take the coefficient of x

-8

Divide by 2

-8/2 =-4

Square it

(-4)^2 =16

Add this to each side

x^2 - 8x+16 = 20+16

x^2 - 8x+16 = 36

The left hand side becomes( x + (-8/2) )^2

(x - 4)^2 = 36

Take the square root of each side

sqrt((x - 4)^2) =±sqrt( 36)

x-4 = ±6

Add 4 to each side

x-4+4 = 4±6

x = 4±6

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3 years ago
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K could either be a 16 or -24
5 0
3 years ago
Data was collected for 300 fish from the North Atlantic. The length of the fish (in mm) is summarized in the GFDT below.
agasfer [191]

Answer:

Class Boundary = 1 between the sixth and seventh classes.

Step-by-step explanation:

              Lengths (mm)                   Frequency

1.                  140 - 143                                  1

2.                 144 - 147                                 16

3.                 148 - 151                                 71

4.                 152 - 155                              108

5.                 156 - 159                               83

6.                 160 - 163                                18

7.                  164 - 167                                 3

The class boundary between two classes is the numerical value between the starting value of the higher class, which is 164 for the 7th class in this case, and the ending value of the class of the lower class, which is 163 for the 6th class in this case.

Therefore the class boundary between the sixth and seventh classes

= 164 - 163  = 1

Therefore Class Boundary = 1.

It can be seen that class boundary for the frequency distribution is 1.

If we take the difference between the lower limits of one class and the lower limit of the next class then we will get the class width value.

Therefore, Class width,

w = lower limit of second class - lower limit of first class

   = 144 - 140

   = 4

7 0
2 years ago
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Answer:

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5 0
3 years ago
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Answer:

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( 5b + 7)² = 5×5b² + 2×5×7b + 7×7 = 25b² + 70b + 49

6 0
2 years ago
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