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Rudik [331]
3 years ago
10

In terms of big data what is variety? Multiple Choice Includes different forms of structured and unstructured data. Includes the

analysis of streaming data as it travels around the Internet. Includes the uncertainty of data, including biases, noise, and abnormalities. Includes the scale of data.
Computers and Technology
1 answer:
nlexa [21]3 years ago
6 0

Answer:

includes different forms of structured and unstructured data.

Explanation:

In terms of big data variety is to include different forms of structured and unstructured data.

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Integers and booleans. Write a program RightTriangle that takes three int command-line arguments and determines whether they con
icang [17]

Answer:

<em>The programming language is not stated;</em>

<em>I'll answer using C++</em>

#include<iostream>

#include<cmath>

using namespace std;

int main()

{

int side1, side2, side3;

cout<<"Enter the three sides of the triangle: "<<endl;

cin>>side1>>side2>>side3;

if(side1<=0 || side2 <= 0 || side3 <= 0) {

 cout<<"Invalid Inputs";

}

else {

 if(abs(pow(side1,2) - (pow(side2,2) + pow(side3, 2)))<0.001) {

  cout<<"Right Angled";

 }

 else if(abs(pow(side2,2) - (pow(side1,2) + pow(side3, 2)))<0.001) {

  cout<<"Right Angled";

 }

 else if(abs(pow(side3,2) - (pow(side2,2) + pow(side1, 2)))<0.001) {

  cout<<"Right Angled";

 }

 else {

  cout<<"Not Right Angled";

 }

}

return 0;

}

Explanation:

The following line declares the three variables

int side1, side2, side3;

The next line prompts user for input of the three sides

cout<<"Enter the three sides of the triangle: "<<endl;

The next line gets user input

cin>>side1>>side2>>side3;

The following if condition checks if any of user input is negative or 0

<em> if(side1<=0 || side2 <= 0 || side3 <= 0) { </em>

<em>  cout<<"Invalid Inputs"; </em>

<em> } </em>

If otherwise

else {

The following if condition assumes that side1 is the largest and test using Pythagoras Theorem

<em>if(abs(pow(side1,2) - (pow(side2,2) + pow(side3, 2)))<0.001) { </em>

<em>   cout<<"Right Angled"; </em>

<em>  } </em>

The following if condition assumes that side2 is the largest and test using Pythagoras Theorem

<em>  else if(abs(pow(side2,2) - (pow(side1,2) + pow(side3, 2)))<0.001) { </em>

<em>   cout<<"Right Angled"; </em>

<em>  } </em>

The following if condition assumes that side3 is the largest and test using Pythagoras Theorem

<em>  else if(abs(pow(side3,2) - (pow(side2,2) + pow(side1, 2)))<0.001) { </em>

<em>   cout<<"Right Angled"; </em>

<em>  } </em>

If none of the above conditions is true, then the triangle is not a right angles triangle

<em>  else { </em>

<em>   cout<<"Not Right Angled"; </em>

<em>  } </em>

}

return 0;

Download cpp
4 0
3 years ago
What may happen if a large number of computer users are attempting to access a Web site at the same time that you are?
pav-90 [236]
B. You may be unable to link to the site. This is due to a large amount of traffic that the network cannot process. Eg. A large number of students or people trying to get through a small doorway.
5 0
3 years ago
B. Write your thoughts about the following in your notebook.
tankabanditka [31]

1. stay with adult supervision

2. check on the web and create a site for it

3. quickly remove it and try not to read it

Explanation:

I really hope this helps

please mark as brainliest

4 0
3 years ago
In which situation would you use a scanner?
mario62 [17]
I think the answer is “ A”
6 0
3 years ago
Read 2 more answers
Write a java program named BMI.java(i)print out your name and your pantherID(ii) Ask user to type in his/her weight and height;
anyanavicka [17]

Answer:

Answered below

Explanation:

//Print name and ID

Scanner x = new Scanner(System.in);

System.out.print("Enter name");

String name = x.nextline();

Scanner y = new Scanner(System.in);

System.out.print("Enter ID");

int id = y.nextline();

System.out.println(name, id);

Scanner w = new Scanner(System.in);

System.out.print("enter weight");

double weight = w.nextline();

Scanner h = new Scanner(System.in);

System.out.print("enter height: ");

double height = h.nextline();

int i = 0;

while( I < 2){

if ( !isDigit(weight) && !isDigit(height){

Scanner w = new Scanner(System.in);

System.out.print("enter weight:);

weight = w.nextline();

Scanner h = new Scanner(System.in);

System.out.print("enter height");

height = h.nextline();

}else{

break;

double BMI = weight / ( height **2)

System.out.print(BMI)}

I++

}

3 0
3 years ago
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