The value of x in the equation (43/7 ÷ x + 32/9) ÷ 25/6 = 4/3 is 43/14
<h3>How to solve for x in the equation?</h3>
The equation is given as:
(43/7 ÷ x + 32/9) ÷ 25/6 = 4/3
Rewrite as a product
(43/7 ÷ x + 32/9) x 6/25 = 4/3
Multiply both sides of the equation by 25/6
(43/7 ÷ x + 32/9)= 4/3 x 25/6
Evaluate the product
(43/7 ÷ x + 32/9)= 50/9
Rewrite the equation as:
43/7x + 32/9= 50/9
Subtract 32/9 from both sides
43/7x = 2
Multiply both sides by 7x
14x = 43
Divide by 14
x =43/14
Hence, the value of x in the equation (43/7 ÷ x + 32/9) ÷ 25/6 = 4/3 is 43/14
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Answer:
The value of the sum is: 
.
Step-by-step explanation:
Given: 
.
Taking 
common outside from the denominator, we have:
We have the following theorem.
If 
is integrable on [0, 1] then 
.
Now, let 
.
Therefore the summation becomes
Hence, the sum is 
/4.
Answer:
the slope is 7
y intercept is -4
Step-by-step explanation:
y-y1 = m(x-x1)
m = (y2-y1) / (x2-x1)
m = (10-3)/(2-1)
m=7/1
y-3=7(x-1)
y-3=7x-7
y=7x-7+3
y=7x-4
JUBILANT
Step-by-step explanation:
