3 years ago

Secants BE and CF intersect at point D inside A. What is the measure of CDE?

1 answer:

6 0

MCE = 360 - (150 + 70 + 50)
mCE = 360 - 270
mCE = 90

<CDE = 1/2(mBE + mCE)
<CDE = 1/2(150 + 90)
<CDE = 1/2(240)
<CDE = 120

answer
<CDE = 120°

You might be interested in

Write the formula for absolute value function if its graph has the vertex at point (0,6) and passes through the point (−1,−2).

valentinak56 [21]

First you need to find the slope of the line:

$m = \frac{y_2 - y_1}{x_2 - x_1}$

m=6-(-2) / (-1)-0 =-8

equation of line is:

y=mx+b

y=-8x+6

for absolute value function:

if x<0

y=-8x+6

if x>0

y=+8x-6

8 0

2 years ago

What is 9/10 of 7 inches

PSYCHO15rus [73]

It is equivalent to 16 cm

4 0

2 years ago

Solve P = 8/3 R + 30 for R.

vampirchik [111]

Answer:

R = (3P-30)/8

Step-by-step explanation:

subtract 30 from each side to get:

P-30 = $\frac{8}{3}$ R

multiply each side by $\frac{3}{8}$ to get:

$\frac{3}{8}$ · P - 30 = R

R = (3P-30)/8

7 0

3 years ago

Can someone help?????

NeX [460]

mean would be adding them all up and dividing by how many there is mean median mode and range but the mean absolute deviation would be actually can't tell you cuz I don't know myself but you could probably look it up I wish you the best of luck

4 0

3 years ago

Can someone step by step explain the answer to me please and thank u

True [87]

First

angle in front of c is 30°, so hypotenuse is equal to 2c

it's right triangle, so let's use Pythagorean theorem\

$(2c)^2=c^2+4^2\\4c^2=c^2+16\\3c^2=16\\\\c^2=\dfrac{16}{3} \\\\c=\dfrac{4}{\sqrt{3} } =\dfrac{4\sqrt{3} }{3 }$

Second

b - the base of the triangle, angles at the base are equal ⇒ cathets are equal

it's right triangle, so let's use Pythagorean theorem

$b^2=7^2+7^2\\b^2=49+49\\b=\sqrt{2\times49} =7\sqrt{2}$

3 0

2 years ago