Question

Using the transformation T: (x, y) (x + 2, y + 1), find the distance named.

Answer 1

Answer:

The distance CC' is $\sqrt5units$

Step-by-step explanation:

Given the transformation T:  (x, y) (x + 2, y + 1)

we have to find the distance CC'

Let coordinate of C are (a,b).

Now, by using transformation T the coordinates of C' are (a+2,a+1)

By using distance formula,

$CC'=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\= \sqrt{(a+2-a)^2+(b+1-b)^2}\\\\=\sqrt{4+1}=\sqrt5 units$

Hence, the distance CC' is $\sqrt5units$

Answer 2

I hope this helps you