The formula<span> for the </span>equation<span> of a </span>circle<span> is (x – h)</span>2+ (y<span> – k)</span>2<span> = r</span>2<span>, where (h, k) represents the coordinates of the </span>center<span> of the </span>circle<span>, and r represents the radius of the </span>circle<span>. If a </span>circle<span> is </span>tangent<span> to the x-</span>axis<span> at (</span>3,0), this means it touches the x-axis at that point. hope this helps
- Ava<3
Answer:
DeShawn pays .67 cent per pound of sugar
Answer:
-8
Step-by-step explanation:
you add 5 to -7 to get -2
7 x -1 is -7
so x = -1
8 x -1 = -8
<h2>Hello!</h2>
The answer is:
C. Cosine is negative in Quadrant III
<h2>
Why?</h2>
Let's discard each given option in order to find the correct:
A. Tangent is negative in Quadrant I: It's false, all functions are positive in Quadrant I (0° to 90°).
B. Sine is negative in Quadrant II: It's false, sine is negative in positive in Quadrant II. Sine function is always positive coming from 90° to 180°.
C. Cosine is negative in Quadrant III. It's true, cosine and sine functions are negative in Quadrant III (180° to 270°), meaning that only tangent and cotangent functions will be positive in Quadrant III.
D. Sine is positive in Quadrant IV: It's false, sine is negative in Quadrant IV. Only cosine and secant functions are positive in Quadrant IV (270° to 360°)
Have a nice day!
