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Ad libitum [116K]
3 years ago
9

What type of angle is shown?​

Mathematics
2 answers:
Strike441 [17]3 years ago
5 0
An obtuse angle because an obtuse is an angle that is greater than 90 degrees but less than 180.
dimaraw [331]3 years ago
3 0

Answer:

B. Obtuse angle

Step-by-step explanation:

Remember that a right angle is 90 degrees and would be like the edge of a square or rectangle going completely vertical. An obtuse angle is larger than 90 degrees so the vertex or point where both lines connect would have both lines farther apart. An acute angle is smaller than a 90-degree angle and is closer to touching the lines (a tip for remembering acute angles could be "a-cute angle" or a smaller cute angle). Hope this helps!

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24 because it’s the lowest multiple of 12 that’s also in 2,6 and 8
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What initial investment must be made to accumulate $60000 in 17 years if the money is invested in a mutual fund that pays 12% an
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$7881.18

Step-by-step explanation:

   Let the initial Investment be P_{0}. The Interest is compounded on a monthly basis at 12% annual interest rate. After 17 years, the Investment amounts to $60,000.

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Since this is a compound interest problem, the total amount can be modeled as follows: P(t)=P_{0}(1+\frac{i}{100})^{t}

Here i is the interest rate, i.e 1, and t is the number of time periods, i.e 17\textrm{ years x }12\frac{\textrm{months}}{\textrm{year}}= 204\textrm{ months}

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0.00084 in scientific notation
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cos theta = 4/5, 0˚< theta < 90˚ use the information given to find sin2theta, cos2theta, and tan 2theta
NikAS [45]
First calculate \sin\theta.

\sin^2\theta+\cos^2\theta=1\\\\\sin^2\theta=1-\cos^2\theta\\\\\sin^2\theta=1-\left(\dfrac{4}{5}\right)^2\\\\\\\sin^2\theta=1-\dfrac{16}{25}\\\\\\\sin^2\theta=\dfrac{9}{25}\quad|\sqrt{(\dots)}\\\\\\\sin\theta=\sqrt{\dfrac{9}{25}}\\\\\\\boxed{\sin\theta=\dfrac{3}{5}}

We take positive value of sinθ because 0° < θ < 90°
Now we could calculate sin2θ, cos2θ and tan2θ:

\sin2\theta=2\sin\theta\cos\theta=2\cdot\dfrac{3}{5}\cdot\dfrac{4}{5}=\dfrac{2\cdot3\cdot4}{5\cdot5}=\dfrac{24}{25}\\\\\\\cos2\theta=\cos^2\theta-\sin^2\theta=\left(\dfrac{4}{5}\right)^2-\left(\dfrac{3}{5}\right)^2=\dfrac{16}{25}-\dfrac{9}{25}=\dfrac{7}{25}\\\\\\&#10;\tan2\theta=\dfrac{\sin2\theta}{\cos2\theta}=\dfrac{\frac{24}{25}}{\frac{7}{25}}=\dfrac{24\cdot25}{7\cdot25}=\dfrac{24}{7}=3\dfrac{3}{7}
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3 years ago
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