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Marta_Voda [28]
2 years ago
13

Triplicate ratio of 2:1 is​

Mathematics
1 answer:
castortr0y [4]2 years ago
3 0

Answer:

8/27

Step-by-step explanation:

The triplicate ratio of 2:3 is 2^3/3^3 = 8/27

HAVE A GREAT DAY!

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Find the perimeter of the figure.
Molodets [167]

Answer:

A) 60

Step-by-step explanation:

P = 5+5+11+9+(5+11)+(9+5)

P = 60

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3 years ago
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Eighteen is 25% less than what number?
Elenna [48]

Answer:

72

Step-by-step explanation:

multiply 18 by 4,

since 100/4 is 25, and four quarters makes a dollar, multiply it by 4

18(4) = 72

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A triangle with an area of 23 cm² is dilated by a factor of 6. What is the area of the dilated triangle? Enter your answer in th
Marizza181 [45]
Given that:
Area of triangle=23 cm²
Dilation factor= 6
It means that the area of the dilated triangle is 6²=36 times of the original.
Now area of dilated triangle, A'=36 x 23 
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Answer: Area of dilated triangle is 828 cm².
7 0
3 years ago
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Confidence Interval Mistakes and Misunderstandings—Suppose that 500 randomly selected recent graduates of a university were as
kvv77 [185]

Answer:

The correct 95% confidence interval is (8.4, 8.8).

Step-by-step explanation:

The information provided is:

n=500\\\bar x=8.6\\\sigma=2.2

(a)

The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

CI=\bar x\pm z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

The 95% confidence interval for the average satisfaction score is computed as:

8.6 ± 1.96 (2.2)

This confidence interval is incorrect.

Because the critical value is multiplied directly by the standard deviation.

The correct interval is:

8.6\pm 1.96 (\frac{2.2}{\sqrt{500}})=8.6\pm 0.20=(8.4,\ 8.6)

(b)

The (1 - <em>α</em>)% confidence interval for the parameter implies that there is (1 - <em>α</em>)% confidence or certainty that the true parameter value is contained in the interval.

The 95% confidence interval for the mean rating, (8.4, 8.8) implies that the true there is a 95% confidence that the true parameter value is contained in this interval.

The mistake is that the student concluded that the sample mean is contained in between the interval. This is incorrect because the population is predicted to be contained in the interval.

(c)

The (1 - <em>α</em>)% confidence interval for population parameter implies that there is a (1 - <em>α</em>) probability that the true value of the parameter is included in the interval.

The 95% confidence interval for the mean rating, (8.4, 8.8) implies that the true mean satisfaction score is contained between 8.4 and 8.8 with probability 0.95 or 95%.

Thus, the students is not making any misinterpretation.

(d)

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we take appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

In this case the sample size is,

<em>n </em>= 500 > 30

Thus, a Normal distribution can be applied to approximate the distribution of the alumni ratings.

7 0
3 years ago
How much of a discount do non chain retailers get on their products?
mariarad [96]
I think non chain retailers wholesale their products at about 50% off retail it really depends on the product.
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