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3 years ago

The two prisms below are similar. What is the value of x?

Mathematics

2 answers:

Alex73 [517]3 years ago

3 0

Answer:

The value of x is D. 30

Step-by-step explanation:

hope it works out!!!!

irina [24]3 years ago

3 0

I think its D. 30 :)

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I'm giving 30 points if you answer correctly!

soldi70 [24.7K]

Answer:

Part A: 64 (right-side 3th cell) and 7 (left-side 4th cell)

Part B: 5 hours- $45; 6 hours- $54; 8 hours- $72

Part C: $5 more

Step-by-step explanation:

Explanation for Part C- We know that if she works 5 hours mowing lawns, she will earn $40. But, when she works at the theme park we use the ratio given to find out how much she earn per hour. In her case she earns $9 for every hour she works at the theme park. now if you multiply that by 5 we can find out how much she earns in 5 hours which is $45. This is $5 more than what she earns mowing lawns for the same amount of time. Here we can conclude that Barbara earns $5 dollars more working at the theme park for 5 hours rather that mowing lawns.

If you can please name me the brainliest that would be much appreciated. Thanks and Good Luck!

4 0

3 years ago

It's a question from real and complex numbers which I can't solve. so someone PLZ HeLp

Semmy [17]

Answer:

$\frac{1}{5}$

Step-by-step explanation:

Using the rules of exponents

$a^{m}$ × $a^{n}$ = $a^{(m+n)}$ , $\frac{a^{m} }{a^{n} }$ = $a^{(m-n)}$ , $(a^m)^{n}$ = $a^{mn}$

Simplifying the product of the first 2 terms

$\frac{a^{p^2+pq} }{a^{pq+q^2} }$ × $\frac{a^{q^2+qr} }{a^{qr+r^2} }$

= $a^{p^2-q^2}$ × $a^{q^2-r^2}$

= $a^{p^2-r^2}$

Simplifying the third term

5( $(a^p+r)^{p-r}$

= 5 $a^{(p+r)(p-r)}$ = 5 $a^{(p^2-r^2)}$

Performing the division, that is

$\frac{a^{(p^2-r^2)} }{5a^{(p^2-r^2)} }$ ← cancel $a^{(p^2-r^2)}$ on numerator/ denominator leaves

= $\frac{1}{5}$

4 0

3 years ago

What is 100 divided by 6

iren2701 [21]

100/6 = 16.66 rounds to 16.7

6 0

3 years ago

Solve this problem please

djyliett [7]

The formula for depreciation is:

$y=x(1-r)^t$

Where x = Initial value,

y= Amount after depreciation.

r= Rate of depreciation,

t = time (in years)

According to given problem,

x = 1040, y= 944 and t = 12 months =1 year.

So, first step is to plug in these values in the above formula, So,

$944 = 1040(1-r)^1$

944 = 1040 (1 -r)

$\frac{944}{1040} =1-r$ Divide each sides by 1040.

0.907692308 =1 - r

0.907692308 - 1 = -r Subtract 1 from each sides.

-0.092307692 = -r

So, r = 0.09 or 9%.

Now plug in 0.09 in the above equation to get the depreciation equation. So,

$y = x (1- 0.09)^t$

So, $y = 0.91x^t$

b) To find the value of the bike after 5 months,

plug in t = 5 months= 5/12 = 0.41667 years in the above equation of depreciation.

So, $y= 1040 *(0.91)^{0.41667}$

y = 1040 * 0.961465659

y = 999.9242852

y = 1000 (Rounded to nearest integer).

Hence, the value of the bike after 5 months is $1000.

7 0

3 years ago

How do you convert minutes to hours

Simora [160]

Easy, just do 60 seconds which equals a minute. Since we know that now simply use 60 minutes to get you to an hour. If your doing minutes to hours make sure there is a 0 at the end.

7 0

3 years ago