Question

X2+6x-3=0 solve by completing the square

Answer 1

To answer the question we need to first see the formula for completing the square, x^2+6x-3=0 is in the form of ax^2+bx-c, a=1, b=6, and c=-3. You'll need to find the constant now, which is nine.

a=1,​ b=6, c=−3  

x^2+6x+9−9−3

Now you need to use another formula, Square of Sum: (a+b)^2=a^2+2ab+b^2 then simplify.

(x+3)^2−9−3=(x+3)^2−12

Now we need to put the simplified equation back into the original equation. After that, take the square root of both sides and make √12 into 2√3.

(x+3)^2=12

x+3=±√12

x+3=±2√3

Now make x+3=±2√3 two different two equations and solve them. After that, collect the solutions and then you'll be finished!

x+3=2√3 & x+3=-2√3

x=2√3-3 & x=-2√3-3

x=2√3-3, -2√3-3

Now you know the answer as well as the formula. Hope this helps, have a BLESSED AND WONDERFUL DAY, as well as an amazing super bowl weekend!

- Cutiepatutie ☺❀❤