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Vaselesa [24]
4 years ago
5

if the recommended daily allowance for vitamin c is 60 mg per day and there are 70 mg of vitamin C per 100 g orange, how many 3.

0 oz oranges would you have to eat each week to meet this requirement
Mathematics
1 answer:
noname [10]4 years ago
8 0

Answer: 7

Step-by-step explanation:

Given : The recommended daily allowance for vitamin c is 60 mg per day .

Then, for one whole week , the recommended allowance for vitamin c will be :-

7\times60=420\text{ mg}

Also, there are 70 mg of vitamin C per 100 g orange.

1 g = 1000 ml

The proportion of Vitamin C in 100 g = \dfrac{70}{100000}=0.0007

1 oz =28.3495 grams

Then, 3\ oz= 3\times28.3495=85.0485 \text{ gm}=85048.5\ mg

Then, amount of vitamin C in 85048.5 mg = 0.0007\times85048.5=59.53395\approx59.53\ mg

Then, the number of oranges have to eat each week to meet this requirement= \dfrac{420}{59.53}\approx7

Hence,  about 7 oranges you would have to eat each week to meet this requirement.

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The student population of a school consists of 300 girls and 500 boys
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Answer:

In all you have 800 students.

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Step-by-step explanation:

Hope this helps?

8 0
3 years ago
In​ Marissa's calculus​ course, attendance counts for 15​% of the​ grade, quizzes count for 20​% of the​ grade, exams count for
Alexandra [31]

Answer:

Her average was 87.35% on this course.

Step-by-step explanation:

In order to determine Marissa's average we need to take the average she has on each of the cattegories and find how much that relates to the weight of the  cattegory on the final grade. We have:

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Quizzes = weigth*(Marissa's average)

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Exams = 50%*(82/100) = 41%

The final exam counts for 15% of the grade and she has a average of 85% on that so we have:

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So her grade is the sum of all the cattegories:

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Step-by-step explanation:

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