Answer: 1 1/6
Step-by-step explanation: i dont know if this is right, but hope it helps
Answer:
Kevin needs 96 points on his last test to raise his mean test score to 90 points.
Step-by-step explanation:
we know that
The mean score is the total of all scores divided by the total number of tests.
Let
x_1 ----> the score in the first math test
x_2 ----> the score in the second math test
x_3 ----> the score in the third math test
x_4 ----> the score in the fourth math test
we have
After taking the first 3 tests, his mean test score is 88 points
so

----> equation A
How many points does he need on his last test to raise his mean test score to 90 points?
so

----> equation B
substitute equation A in equation B

solve for x_4


Therefore
Kevin needs 96 points on his last test to raise his mean test score to 90 points.
--------------------------------------------------------------------
Define x :
--------------------------------------------------------------------
Let the smallest number be x.
First number = x
Second Number = x + 1
Third Number = x + 2
--------------------------------------------------------------------
Construct equation :
--------------------------------------------------------------------
x(x+2) - (x+1) = 7(x+2) + 1
--------------------------------------------------------------------
Solve x :
--------------------------------------------------------------------
x(x + 2) - (x + 1) = 7(x + 2) + 1
x² + 2x - x - 1 = 7x + 14 + 1
x²- 6x - 16 = 0
<span>(x+2)(x-8) = 0
</span>x = -2 or x = 8
Since x is a positive integer, it cannot be negative.
⇒x = 8
--------------------------------------------------------------------------
Answer: The three numbers are 8, 9 and 10.
--------------------------------------------------------------------------
<span>15x + 35y - 40 z = 5 (3x + 7y -8z)
hope that helps
............................</span>
Answer:
see below
Step-by-step explanation:
The mapping tells you how to find the vertices of the image:
(x, y) ⇒ (x +2, y -3)
S(-3,-2) ⇒ S'(-3 +2, -2 -3) = S'(-1, -5) . . . . . matches choice D
T(-4, 3) ⇒ T'(-4 +2, 3 -3) = T'(-2, 0)
V(-2, 3) ⇒ V'(-2 +2, 3 -3) = V'(0, 0)