All categories

2 years ago

Boubacar went to the store to buy some walnuts. The price per pound of the walnuts

Mathematics

1 answer:

Inessa05 [86]2 years ago

7 0

Answer:

Step-by-step explanation:

Price per pound of the walnuts = $ 6.50

Price of 4 pounds of the walnuts = 4 *6.50 = $ 26

Amount needs to be paid = Price of 4 pounds of walnut - coupon amount

= 26 - 3.75

= $ 22.25

Expression:

Cost to buy p pounds of walnuts = p * 6.50 = 6.5p

Cost to buy p pounds of walnuts, assuming at least one pound is purchased = 6.50 + 6.5p

You might be interested in

Which equation models the problem below if c represents the number of babies whose eyes are closed? There are 12 babies in a pho

Pavel [41]

The correct answer is: 9 + c = 12

Further explanation:

Given

c = number of babies whose eyes are closed

So,

If the total number of babies are 12 then the sum of babies with eyes closed and eyes opened should be equal to 12.

As c is the number of babies with eyes closed and 9 is the number of babies with eyes opened then,

$9+c = 12$

The equation can be used to find the number of babies whose eyes are open

$9+c-9 = 12 -9\\c = 3$

Three babies have their eyes closed in the photograph.

Keywords: Linear equations, Word problems

Learn more about linear equations at:

#LearnwithBrainly

5 0

2 years ago

Find the limit

Lana71 [14]

Step-by-step explanation:

<h3>Appropriate Question :-</h3>

Find the limit

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]$

$\large\underline{\sf{Solution-}}$

Given expression is

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]$

On substituting directly x = 1, we get,

$\rm \: = \: \sf \dfrac{1-2}{1 - 1}-\dfrac{1}{1 - 3 + 2}$

$\rm \: = \sf \: \: - \infty \: - \: \infty$

which is indeterminant form.

Consider again,

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]$

can be rewritten as

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( {x}^{2} - 3x + 2)}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( {x}^{2} - 2x - x + 2)}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( x(x - 2) - 1(x - 2))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ {(x - 2)}^{2} - 1}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 2 - 1)(x - 2 + 1)}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 3)(x - 1)}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 3)}{x(x - 2)}\right]$

$\rm \: = \: \sf \: \dfrac{1 - 3}{1 \times (1 - 2)}$

$\rm \: = \: \sf \: \dfrac{ - 2}{ - 1}$

$\rm \: = \: \sf \boxed{2}$

Hence,

$\rm\implies \:\boxed{ \rm{ \:\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right] = 2 \: }}$

$\rule{190pt}{2pt}$

7 0

2 years ago

Read 2 more answers

4(x−3)≥56=<br> Please helppppp

pickupchik [31]

Answer:x≥17

Step-by-step explanation:

Let's solve your inequality step-by-step.

4(x−3)≥56

Step 1: Simplify both sides of the inequality.

4x−12≥56

Step 2: Add 12 to both sides.

4x−12+12≥56+12

4x≥68

Step 3: Divide both sides by 4.

4x4≥6

x≥17

7 0

2 years ago

Harold bought 5 apples for $ 1.30. What is the unit price?

Firdavs [7]

What is unit price?- unit price is the cost of one item(which in this case is an apple)

5 apples- $1.30
1 apple- 1.30 / 5
= $0.26

7 0

2 years ago

Jessica has 120 stamps in a collection she bought 16 more Jessica wants plays the stamps equally and six pages of the book how m

BabaBlast [244]

Answer:

30 stamps each

Step-by-step explanation:

This is the correct question:

Jessica has 120 stamps in a collection she bought 60 more Jessica wants to place the stamps equally and 6 pages of a book how many stamps will be on each page of the book

Total stamps = 120 + 60

= 180

Jessica wants to place the stamps equally on 6 pages of a book

how many stamps will be on each page of the book?

Each page of the book = Total stamps / number of pages in the book

= 180 / 6

= 30

Each page of the book will have 30 stamps each

8 0

2 years ago