PLSSSSSHELP!!! the image is attached

A new car is available with standard or automatic transmission, two or four doors, and it is available in 10 exterior colors. Wh

dezoksy [38]

Answer:

Step-by-step explanation:

Given that:

Number of options available for transmission = 2 (Standard or Automatic)

Number of options for doors = 2 (2 doors or 4 doors)

Number of exterior colors available = 10

To find:

Total number of outcomes = ?

Solution:

First of all, let us calculate the number of outcomes for the transmission mode and number of doors options.

1. Standard - 2 doors

2. Standard - 4 doors

3. Automatic - 2 doors

4. Automatic - 4 doors

Number of outcomes possible = 4 (which is equal to number of transmission mode available multiplied by number of doors options i.e. 2 $\times 2$ )

Now, these 4 will be mapped with 10 different exterior colors.

Therefore total number of outcomes possible :

Number of transmission modes $\times$ Number of doors options $\times$ Number of exterior colors

2 $\times$ 2 $\times$ 10 = <em>40</em>

3 0

3 years ago

A certain brand of dinnerware set comes in three colors: red, white, and blue. Twenty percent of customers order the red set, 45

denis23 [38]

Answer:

a) 0.20

b) 0.45

c) 0.65

d) Yes

e) Yes

f) Z = X + Y (except when X = 1 and Y = 1)

This is because the successes of X and Y are mutually exclusive events but their failures aren't. X and Y cannot both be 1.

Step-by-step explanation:

Probability of a red set = 20% = 0.20

Probability of a white set = 45% = 0.45

Probability of a blue set = 35% = 0.35

Probability of the single set being a red or white set = 20% + 45% = 65% = 0.65

P(X=1) = 0.20, P(X=0) = 1 - 0.2 = 0.80

P(Y=1) = 0.45, P(Y=0) = 1 - 0.45 = 0.55

P(Z=1) = 0.65, P(Z=0) = 1 - 0.65 = 0.35

a) pX = P(X=1) = 0.20

b) pY = P(Y=1) = 0.45

c) pZ = P(Z=1) = 0.65

d) Since only one order is being considered at a time, it isn't possible to order red & white set in a single set, hence, both X and Y cannot both be successes (equal to 1) at the same time. But they can both be failures (both equal to 0) if a blue set is ordered. The successes of X and Y are mutually exclusive events but their failures aren't

e) Is pZ = pX + pY

pX = 0.2, pY = 0.45, pZ = 0.65

Hence, this statement is correct!

f) Z = X + Y

Let's check all the probabilities

when X = 1 and Y = 1, Z = 1

1 ≠ 1 + 1

when X = 0 and Y = 1, Z = 1

1 = 0 + 1

when X = 1 and Y = 0, Z = 1

1 = 1 + 0

when X = 0 and Y = 0, Z = 0

0 = 0 + 0

Hence, Z = X + Y (except when X = 1 and Y = 1)

This is because the success of X and Y are mutually exclusive events but their failures aren't.

8 0

3 years ago

which of the following terms best describes the graph of the exponential function given below f(x)=4*5^x

N76 [4]

If i did it right the anwser is 20

4 0

3 years ago

2/15 + 27/35 = what in reduced terms

solniwko [45]

2/15 + 27/35 = 14+81 /105 = 95/105 = 19/21

so, your answer is 19/21

8 0

3 years ago

Find the volume of the composite figure

AURORKA [14]

39in³ is a required volume.

Solution given:

for upper one

length[l]=8in

breadth[b] =3in

height[h]=1in

now

volume [V1]=l×b×h=8×3×1=24in³

again for lower one:

length[l]=6-1=5in

breadth[b] =3in

height[h]=1in

volume [V2]=l×b×h=5×3×1=15in³

Again

total volume =V1+V2=24in³+15in³=39in³

6 0

3 years ago

￼PLSSSSSHELP!!! the image is attached

PLSSSSSHELP!!! the image is attached