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3 years ago

Pls answer this ASAP I need it by the end of the day

Mathematics

1 answer:

iVinArrow [24]3 years ago

6 0

Answer:

Step-by-step explanation:

Let's calculate sinA and sinB.

sinA = opposite / hypotenuse = 12 / 20

sinB = opposite / hypotenuse = 16 / 20

Since 12 / 20 ≠ 16 / 20, she is incorrect.

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The volume of a cylinder with a height of 4 feet is 144n cubic feet what is the radius of the base of the cylinder V=nr2h

geniusboy [140]

Answer: 6 ft

Step-by-step explanation:

$144\pi =\pi(r^{2})(4)\\\\144\pi=4\pi r^{2}\\\\36=r^{2}\\\\r=\boxed{6 \text{ ft}}$

6 0

2 years ago

What is the 1st quartile? (median of lower half) 240 235 230

postnew [5]

Answer:

lower half

Step-by-step explanation:

The first quartile in this is 230

8 0

3 years ago

Read 2 more answers

NEED HELP 10 POINTS

leonid [27]

48.8 megabytes. When the download is 17.5% complete, have been downloaded 48.8 megabytes.

The key to solve this problem is using the rule of three.

If 279Mb -------------> 100%

x <------------- 17.5%

x = [(279 megabytes)(17.5)]/100

x = 48.825 megabytes

Round to the nearest tenth 48.8 megabytes.

6 0

4 years ago

How many quarts of pure antifreeze must be added to 8 quarts of a 40% antifreeze solution to obtain a 60% antifreeze solution?

Vinvika [58]

Answer:

we have 8 quarts of 40% antifreeze,

according to the britain equivalent, 1 quart = 1.13L

so, we have 8 * 1.13L = 9.04 L

out of the 9.04 L, 40% is antifreeze

amount of antifreeze = 0.4 * 9.04 = 3.616 L

moles of antifreeze present = 3.616/22.4 = 0.16 moles

moles of antifreeze in 60% solution = 0.6 * v/22.4 = 0.027 * v

(where v is the volume of final solution)

molarity of initial solution = 0.16/9.04 = 0.018 M

molarity of final solution = 0.027*v/v = 0.027 M

m1*v1 = m2*v2

0.018 * 9.04 = 0.027 * v

v = 0.018 * 9.04/0.027

v = 6.026 L

amount if antifreeze in the final solution = 6.026 * 0.027 =

0.163 Moles of antifreeze

amount in L = 0.163 * 22.4 = 3.65 L

amount in quarts = 3.65/1.13 = 3.23 quarts

4 0

3 years ago

If EF bisects CD, CG =5x-1, GD = 7x-13, EF = 6x-4, and GF =13, find EG

VARVARA [1.3K]

Greetings from Brasil....

As stated in the statement of the question, EF is a bisector of CD, so point G is the median point of CD, so CG = GD

5X - 1 = 7X - 13

X = 6

EF = EG + GF

6X - 4 = EG + 13 x = 6, so

6·6 - 4 = EG + 13

(see attachment)

6 0

3 years ago