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Andreyy89
3 years ago
10

Pls answer this ASAP I need it by the end of the day

Mathematics
1 answer:
iVinArrow [24]3 years ago
6 0

Answer:

No

Step-by-step explanation:

Let's calculate sinA and sinB.

sinA = opposite / hypotenuse = 12 / 20

sinB = opposite / hypotenuse = 16 / 20

Since 12 / 20 ≠ 16 / 20, she is incorrect.

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What is the answers to the question: Which rational expression is undefined when x = 0?
Rom4ik [11]

Answer:

option D

\frac{4x-8}{-2x^2}

Step-by-step explanation:

An expression is undefined when you get division by zero or in simple words when denominator is zero.

Now we will solve each expression one be one by plugging value of x = 0

<h3>1)</h3><h3>\frac{5x^2-4}{3x-3}</h3>

\frac{5(0)-4)}{3(0)-3}

-4/-3 = 4/3

<h3>2)</h3><h3>\frac{6x^2}{9x-3}</h3>

\frac{6(0)}{9(0)-3}

0/-3 = 0

<h3>3)</h3>

\frac{8x+6}{-x^2+1}

\frac{8(0)+6}{-0+1}

6/1

6

<h3>4)</h3>

\frac{4x-8}{-2x^2}

\frac{4(0)-8}{-2(0)}

<h3>-8/0</h3><h3>undefined</h3>

8 0
2 years ago
Read 2 more answers
Help me on this please:(
Dima020 [189]

Answer:

3:20   3/20   3.20

Step-by-step explanation:

4 0
2 years ago
Roots of Quadratics 50 PTS!!!
noname [10]

The values of k for the different quadratic equation solutions are as follows

a  the equation 2x² - x + 3k = 0 has two distinct real roots

  • k < 1/24

b. the equation 5x² - 2x + (2k − 1) = 0 has equal roots

  • k = 3/5

ci the equation -x² + 3x + (k + 1) = 0 has real roots

  • k > -3.25

d the equation 3kx² - 3x + 2 = 0 has no real solutions

  • k < ± 1.633

<h3>How to solve quadratic equations to get different answers</h3>

Quadratic equations of the form ax² + bx + c = 0 is solved using the formula

-b+\frac{\sqrt{b^{2}-4ac } }{2a}     OR     -b-\frac{\sqrt{b^{2}-4ac } }{2a}

The equation b² - 4ac is called the discriminant and it is used as follows

To solve the equation and get two real roots: 2x² - x + 3k = 0

  • b² - 4ac > 0

substituting the values gives

(-1)² - 4 * 2 * 3k > 0

1 - 24k > 0

1 > 24k

divide through by coefficient of k

k < 1/24

To solve the equation and get equal roots: 5x² - 2x + (2k − 1) = 0

  • b² - 4ac = 0

substituting the values gives

(-2)² - 4 * 5 * (2k - 1) = 0

4 - 40k + 20 = 0

-40k = -24

divide through by coefficient of k

k = 3/5

To solve the equation and get real roots  -x² + 3x + (k + 1) = 0

  • b² - 4ac > 0

substituting the values gives  

(3)² - 4 * -1 * (k+1) > 0

9 + 4k + 4> 0

4k > -13

divide through by coefficient of k

k > -3.25

To solve the equation and get  no real solutions  3kx² - 3x + 2 = 0

  • b² - 4ac < 0

substituting the values gives  

(-3)² - 4 * 3k * 2 < 0

9 - 24k² > 0

9 > 24k²

divide through by coefficient of k²

k² < 24/9

k < ± 1.633

Learn more about roots of quadratic equations: brainly.com/question/26926523

#SPJ1

4 0
7 months ago
Read 2 more answers
Can someone help please ?
MAVERICK [17]

Answer:

B because Comp A is $60 for sure plus $42.95 per month and Comp B is $25 for sure and $49.95 per month

7 0
2 years ago
Lorena and Sebastian are both five years old. Every year they each get a cash present from their ncighbor.
Sonja [21]

14,  she will be 14 when she has more

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3 years ago
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