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Volgvan
3 years ago
15

How do you find the slope of the line that goes through the points (-5, 6) and (7,-6)?

Mathematics
1 answer:
strojnjashka [21]3 years ago
5 0

Answer:

Step-by-step explanation:

slope=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\=\frac{-6-6}{7-[-5]}\\\\=\frac{-12}{7+5}\\\\=\frac{-12}{12}\\\\=-1

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What is the product ?
Aneli [31]
Answer: 25x^2 - 1^2

Explanation:

(5x+1) (5x-1)

(5x)^2 - 1^2

25x^2 - 1^2
7 0
2 years ago
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I NEED HELP I GIVE U BRAINLIEST OR WHATEVER
Anna71 [15]

Answer:

B

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
3. Given the following similar triangles. Find the values of variables and label all the unknown angles
astraxan [27]

Answer:

The answer to your question is x = 6 and y = 9

Step-by-step explanation:

Data

AB = x                     DF = 18

BC = 5                     FE = 15

AC = 3                     DE = y

Process

1.- Find y

Use proportions to find it

                 DE/FE = AC/BC

Substitution

                 y/15 = 3/5

Solve for y

                  y = 15(3/5)

                  y = 45/5

                  y = 9

2.- Find x

                AB/DF = BC/FE

Substitution

                x/18 = 5/15

Solve for x

                x = 18(5/15)

                x = 90/15

                x = 6

8 0
4 years ago
The formula for the area of a square is s2, where s is the side length of the square. What is the area of a square with a side l
levacccp [35]

36

area of square = s²

given s = 6 , then

area = 6² = 36



8 0
3 years ago
Someone help me with number 8
Gnesinka [82]

Answer:

The answers are...:

The common ratio is -3

the sequence of the function is 2,-6, 18, -54, 162

and

the sequence of the function model is geometric

I hope this helps ^^"

Step-by-step explanation:

the common ratio is just from the -3 itself

the sequence model is just plugging n for every term so

a(1) would equal to 2, a(2)=-6 , a(3) would equal to -18, etc

and the geometric is bc it has the exponential that has (n-1), thus it is a geometric sequence

6 0
3 years ago
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