Answer:
20
Step-by-step explanation:
Total no = 75
N (P) = 48 , N (H) = 45 , N (T) = 58
N (P∩H) = 28 , N (H∩T) = 37 , N (P∩T) = 40
N (P∩H∩T) = 25
Total no = N (P) + N (H) + N (T) - N (P∩H) - N (H∩T) - N (P∩T) + N (P∩H∩T) + neither
75 = 48 + 45 + 58 - 28 - 37 - 40 + 25 + neither
75 = 71 + neither → neither = 4
N (only P) = N (P) - N (P∩H) - N (P∩T) + N (P∩H∩T) = 48 - 28 - 40 + 25 = 5
N (only H) = N (H) - N (P∩H) - N (H∩T) + N (P∩H∩T) = 45 - 28 - 37 + 25 = 5
N (only T) = N (T) - N (H∩T) - N (P∩T) + N (P∩H∩T) = 58 - 37 - 40 + 25 = 6
So, total liking either one or neither = 4 + 5 + 5 + 6 = 20
Answer:
I need help with the same thing-
Step-by-step explanation:
Answer:
replace one question with itself where the same quantity is added to both sides and yes
Step-by-step explanation:
The other answer is wrong :)
The answer is 5. Measure r and t are congruent. Measure r is 20 so measure t is also 20. So by dividing 20 by 4 you get 5.
A jar of jelly beans contains 50 red gumballs , 45 yellow gumballs, and 30 green gumballs. You reach into the jar and randomly
select a jelly bean, then select another without
putting the first jelly bean back. What is the
probability that you draw two red jelly beans? This is Dependent because you didnt put the other jelly bean in thus changing the total nmber of jelly beans.
A jar of jelly beans contains 50 red gumballs<span> , 45 yellow gumballs, and 30 green gumballs. You reach into the jar and randomly select a jelly bean, then select another while replacing the first jelly bean back. What is the probability that you draw two red jelly beans? This is Independent because you put the other jelly bean in thus keeping the total number of jelly beans.</span>
