48 divided by4 +c^3, c=2

Which of the following expressions is written in simplest form

nadya68 [22]

Answer: I x^2 y^3 z

Step-by-step explanation:

This is the one most simplified. I’ll tell you why the others are incorrect.

F) 3^5 x^2 can be simplified. 3^5= 243. The simplified answer would be 243 x^2

G) (5y)^3= 125y^3

H) a^0 b (^0= 1 always) -> ab

Hope this helps!

3 0

3 years ago

∠A and ∠B are vertical angles. ∠A = 65x − 12 and ∠B = 43x + 10 How many degrees are in ∠A?

Margarita [4]

Answer:

53 degrees

Step-by-step explanation:

Vertical angles are congruent so...

65x-12=43x+10

22x=22

x=1

Then add it into the equation of ∠A

m∠A= 65(1)-12

65-12

53

7 0

3 years ago

Find the inverse of the function y = x2 – 12

vivado [14]

Answer: $y=\sqrt{x+12}$

Step-by-step explanation:

I hope you mean y = x² - 12 and not y = 2x - 12.

You switch the y and x variables:

x = y² - 12

And solve for y:

x + 12 = y²

$y=\sqrt{x+12}$

7 0

3 years ago

The height of a punted football can be modeled with the quadratic function 0.01x^2 + 1.18x+2.

Fantom [35]

The function of the path of the punted ball is a quadratic function which

follows the path of a parabola.

The correct responses are;

Part A: The coordinates of the vertex is $\underline {(59, \, 36.81)}$

Part B: The maximum height of the punt is 36.81 ft.

Part C: The defensive player must reach up to 7.65 feet to block the punt.

Part D: The distance down the field the ball will go without being blocked is approximately 119.67 ft.

Reasons:

The function for the height of the punted ball is; h = -0.01·x² + 1.18·x + 2

Assumption; The distances are feet.

Part A: By completing the square, we have;

f(x) = -0.01·x² + 1.18·x + 2

100·f(x) = -x² + 118·x + 200

-100·f(x) = x² - 118·x - 200

x² - 118·x + (118/2)²= 200 + (118/2)²

(x - 59)² = 200 + (59)² = 3681

(x - 59)² - 3681

At the vertex, -3281 = -100·f(x)

∴ f(x) at the vertex = -3681/-100 = 36.81

$\mathrm{\underline{Coordinate \ of \ the \ vertex = (59, \, 36.81)}}$

Part B: The maximum height is given by the y-value at the vertex = 36.81 ft.

Part C: When x = 5, we have;

h = -0.01·x² + 1.18·x + 2

h = -0.01 × 5² + 1.18 × 5 + 2 = 7.65

The defensive player must reach up to 7.65 feet to block the punt

Part D: The distance the ball will go before it hits the ground is given by

the function, for the height as follows;

h = -0.01·x² + 1.18·x + 2 = 0

From the completing the square method, above, we get;

-0.01·x² + 1.18·x + 2 = 0

x² - 118·x - 200 = 0

x² - 118·x + (118/2)²= 200 + (118/2)²

x² - 118·x + (59)²= 200 + (59)² = 3681

(x - 59)² = 3681

x - 59 = ±√3681

x = 59 ± √3681

x = 59 + √3681 ≈ 119.67

The distance down the field the ball will go without being blocked, x ≈ 119.67 ft.

Learn more here:

brainly.com/question/24136952

5 0

3 years ago

Turn and Talk How are solving 2x + 4 = 20 and 2x - 4 = 20 alike? How are they different?

hjlf

Answer:

they are both alike because you're dividing both equations by 2 . in both equations you're trying to get the variable by itself .

they are both different because both of the equations have a different x= . in equation 1 you subtract and in equation 2 you would add .

Step-by-step explanation:

For 2x+4=20 you would make +4 negative 4 to get the variable by itself .

then you'd subtract the numbers 20-4=16

then divide both sides by 2 2÷2 and 16÷2

x=8 is your answer

for 2x-4=20 you would make -4 and make it positive 4 to get the variable by itself

then you'd add the numbers 20+4

then divide both sides by 2 2÷2 and 24÷2

x=12

4 0

3 years ago