How do you convert 65 degrees Fahrenheit to Celsius?

Mathematics

2 answers:

svlad2 [7]3 years ago

8 0

Answer: 65 degrees Fahrenheit = 18.33 degrees Celsius

Leya [2.2K]3 years ago

6 0

T(°C) = (68°F - 32) × 5/9 = 20 °C

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Plz answer this question

Korvikt [17]

Answer:

-12b+6c+18

Step-by-step explanation:

you just need to add the same numbers and stuff

like -4b+(-8b)=-12 and so on

hope this helps ^^

7 0

2 years ago

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If f(x) = −2 + 8, what is f(−1.8)?<br> 4<br> 6<br> 10<br> 12

Oksanka [162]

F(x) = -2 + 8

f(x) = 6

No matter what x is, it does not change the value of f(x).

f(-1,8) = 6

Answer: 6

5 0

3 years ago

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In ΔABC, the lengths of a, b, and c are 22.5 centimeters, 18 centimeters, and 13.6 centimeters, respectively.

Irina-Kira [14]

Given the values of the three sides of the triangle, we can apply the Cosine Law to find the angles of the triangle. Recall that for we can express the value of c through the equation below.

$c^{2} = a^{2} + b^{2} - 2abcosC$

Rearranging this equation, we can find the value ∠C as shown below.

$\cos C = \frac{a^{2}+b^{2}-c^{2}}{2ab}$
$C = cos^{-1} (\frac{a^{2}+b^{2}-c^{2}}{2ab})$

We can apply the same reasoning for finding the value of ∠B as shown.

$B = cos^{-1} (\frac{a^{2}+c^{2}-b^{2}}{2ac})$

Plugging in the values of the sides (see image attached) from the given. It will now be straightforward to compute for ∠B and ∠C.

$C = cos^{-1} (\frac{22.5^{2}+18^{2}-13.6^{2}}{2(22.5)(18)})$
$C \approx 37.19$

$B = cos^{-1} (\frac{22.5^{2}+13.6^{2}-18^{2}}{2(22.5)(13.6)})$
$B \approx 53.13$

Answer: ∠C = 37.19° and ∠B = 53.13°