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SpyIntel [72]
3 years ago
12

How do you convert 65 degrees Fahrenheit to Celsius?

Mathematics
2 answers:
svlad2 [7]3 years ago
8 0

Answer: 65 degrees Fahrenheit = 18.33 degrees Celsius

Leya [2.2K]3 years ago
6 0
T(°C) = (68°F - 32) × 5/9 = 20 °C
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John was swimming for hour anda half hours at a speed of 2 miles per hour.How far did he swim?
Marrrta [24]

Answer:

3 miles

Step-by-step explanation:

2+1=3 znnsndndnndjd

5 0
3 years ago
Read 2 more answers
Scientific notation<br> 9.78 × 10^5 - 732,000<br> It has to be either 2.46 × 10^5 or 2.46 × 10^3
Morgarella [4.7K]

Answer:

2.46\times 10^5

Step-by-step explanation:

9.78 \times 10^5 - 732,000\\= 9.78 \times 10^5 - 7.32 000\times 10^5\\= 9.78 \times 10^5 - 7.32\times 10^5\\= 2.46\times 10^5

3 0
3 years ago
What is an equation in point-slope form for the line that passes through the points (−3,5) and (2,−3)?
fredd [130]
(-3,5). (2,-3)
x1,y1. x2,y2

y2-y1. -3-5. -8
--------- = ------- = ----- =8 =m
x2-x1. 2-3. -1

plug the rest in

4 0
3 years ago
What is -29.9 - 4.6?<br> O A. -6,5<br> B. 65<br> C. 0.65<br> D. -65
natulia [17]
-6.5 which in your answer choices is a
7 0
2 years ago
Use the definition mtan=lim
Leokris [45]

(a) mtan refers to the slope of the tangent line. Given <em>f(x)</em> = 9 + 7<em>x</em> ², compute the difference quotient:

\dfrac{f(x+h)-f(x)}h = \dfrac{(9+7(x+h)^2)-(9+7x^2)}h = \dfrac{(9+7x^2+14xh+7h^2)-9-7x^2}h = \dfrac{14xh+7h^2}h

Then as <em>h</em> approaches 0 - bearing in mind that we're specifically considering <em>h</em> <em>near</em> 0, and not <em>h</em> = 0 - we can eliminate the factor of <em>h</em> in the numerator and denominator, so that

m_{\rm tan} = \displaystyle \lim_{h\to0}\frac{f(x+h)-f(x)}h = \lim_{h\to0}\frac{14xh+7h^2}h = \lim_{h\to0}(14x+7h) = 14x

and so the slope of the line at <em>P</em> (0, 9), for which we take <em>x</em> = 0, is 0.

(b) The equation of the tangent line is then <em>y</em> = 9.

4 0
2 years ago
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