When two balanced dice are rolled, the sum of the dice can be 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, or 12, giving 11 possibilities. th
RUDIKE [14]
False.
There are 36 possible outcomes, corresponding to numbers 1-6 independently appearing on each of the dice. Only one of those outcomes is double-sixes, resulting in a sum of 12. The probability that the sum is 12 is 1/36.
In short, the 11 outcomes listed in your problem statement are not equally-likely.
here is the answer I just took a picture because I already answered this for someone eles
Anwser: 4x^5-3x^4-4x^3+8x^2-5
Step-by-step explanation:
yes
Answer:
-3/5
Step-by-step explanation:
10-8/4-12=-0.6=-3/5
