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Marat540 [252]
3 years ago
14

Sarah counted 16 dogs playing fetch out of 24 total dogs at the park. which fraction represents the ratio of dogs that were play

ing fetch to total dogs?
Mathematics
1 answer:
mamaluj [8]3 years ago
6 0
It's 16:24
so the ratio is 2:3
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A cube with a side of 1m was sawn into cubes with a side of 1 cm and then laid in a row (in a straight line). What was the lengt
MrRissso [65]

Answer:

10 km

Step-by-step explanation:

volume of cube = s^3

1 m = 100 cm

volume = s^3 = (1 m)^3 = (100 cm)^3 = 1,000,000 cm^3

Since 1 m^3 = 1,000,000 cm^3, when you lay down the 1-cm cubes in a straight line with the edges touching, the line is 1,000,000 cm long.

1,000,000 cm = 10,000 m = 10 km

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Mia had $22. Then she started to receive $4 a week as an allowance. She plans to save all of her money for a bicycle and draws a
saw5 [17]

Answer:

first y then x because y represents 22 and x represents 4 a week.

8 0
3 years ago
Which function is a shrink of the exponential growth function shown on the graph?
fgiga [73]
The exponential function shown in the graph is 3^x, so (1/2)3^x is a shrink of it.

Selection B is appropriate.
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Explain how you know which coins could be used to show 0.77 of a dollar
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you can use 3 quarters and 2 pennies
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A local car dealer claims that 25% of all cars in San Francisco are blue. You take a random sample of 600 cars in San Francisco
sammy [17]

Answer:

No, we can't reject the dealer's claim with a significance level of 0.05.

Step-by-step explanation:

We are given that a local car dealer claims that 25% of all cars in San Francisco are blue.

You take a random sample of 600 cars in San Francisco and find that 141 are blue.

<u><em>Let p = proportion of all cars in San Francisco who are blue</em></u>

SO, Null Hypothesis, H_0 : p = 25%   {means that 25% of all cars in San Francisco are blue}

Alternate Hypothesis, H_A : p \neq 25%   {means that % of all cars in San Francisco who are blue is different from 25%}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

                                  T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p = sample proportion of 600 cars in San Francisco who are blue =   \frac{141}{600} = 0.235

            n = sample of cars = 600

So, <u><em>test statistics</em></u>  =  \frac{0.235-0.25}{{\sqrt{\frac{0.235(1-0.235)}{600} } } } }

                               =  -0.866

<em>Now at 0.05 significance level, the z table gives critical values of -1.96 and 1.96 for two-tailed test. Since our test statistics lies within the range of critical values of z so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.</em>

Therefore, we conclude that 25% of all cars in San Francisco are blue which means the dealer's claim was correct.

4 0
3 years ago
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