A division of the Gibson Corporation manufactures bicycle pumps. Each pump sells for $10, and the variable cost of producing eac
1 answer:
Answer:
12,500 units
Step-by-step explanation:
Given:
Selling cost of the pump = $10
Variable cost of producing each unit = 60% of selling cost
or
Variable cost of producing each unit = 0.60 × $10 = $6
Monthly fixed cost = $50,000
Now,
The profit per unit = Selling cost - Variable cost
or
The profit per unit = $10 - $6 = $4
Therefore,
The breakeven point =
or
the breakeven point =
or
the breakeven point = 12,500 units
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<u>Answer:</u>
The length of VI to the nearest tenth is 4 cm
Solution:
The plot is like a quadrilateral and the fences are built on the diagonal
We know that for quadrilateral both the diagonals are in same height,
So as per the picture,
Now we know that
Hence,
<u>Rounding off:</u>
- If the number that we are rounding is followed by 5 to 9, then the number has to be increased to the next successive number.
- If the number that we are rounding is followed by 1 to 4, then the number has to remain the same.
Here the number to be round off is 3.98, 9 belongs to the first category stated above. So, 3 is increased to 4.
Hence, the length of VI = 4 cm.
So hmm let's take a peek at the cost first
so, they chartered the plane for 150 folks with a fixed cost of 250,000
now, incidental fees are 300 per person, if we use the quantity "x", for how many folks, then if "x" persons are booked, then incidental fees are 300x
so, more than likely an insurance agency is charging them 300x for coverage
anyway, thus the cost C(x) = 250,000 + 300x
now, the Revenue R(x), is simple is jut price * quantity
well, the price, thus far we know is 5000 for 80 folks, but it can be lowered by 30 to get one more person, thus increasing profits
so... let's see what the price say y(x) is
so.. now we know y(x) = -30x+7400
now, Revenue is just price * quantity
the price y(x) is -30x+7400, the quantity is "x"
that simply means R(x) = -30x²+7400x
now, for the profit P(x)
the profit is simple, that is just incoming revenue minus costs, whatever is left, is profit
so P(x) = R(x) - C(x)
P(x) = (7400x - 30x²) - (250,000+300x)
P(x) = -30x² + 7100x - 250,000
now, where does it get maximized? namely, where's the maximum for P(x)?
well
and as you can see, if you zero out the derivative, there's only 1 critical point, run a first-derivative test on it, to see if its a maximum
so, they chartered the plane for 150 folks with a fixed cost of 250,000
now, incidental fees are 300 per person, if we use the quantity "x", for how many folks, then if "x" persons are booked, then incidental fees are 300x
so, more than likely an insurance agency is charging them 300x for coverage
anyway, thus the cost C(x) = 250,000 + 300x
now, the Revenue R(x), is simple is jut price * quantity
well, the price, thus far we know is 5000 for 80 folks, but it can be lowered by 30 to get one more person, thus increasing profits
so... let's see what the price say y(x) is
so.. now we know y(x) = -30x+7400
now, Revenue is just price * quantity
the price y(x) is -30x+7400, the quantity is "x"
that simply means R(x) = -30x²+7400x
now, for the profit P(x)
the profit is simple, that is just incoming revenue minus costs, whatever is left, is profit
so P(x) = R(x) - C(x)
P(x) = (7400x - 30x²) - (250,000+300x)
P(x) = -30x² + 7100x - 250,000
now, where does it get maximized? namely, where's the maximum for P(x)?
well
and as you can see, if you zero out the derivative, there's only 1 critical point, run a first-derivative test on it, to see if its a maximum